<span>Nitrogen trifluoride - NF3.
1 mol NF3 contains 1 mol atoms of Nitrogen
2.49 mol NF3 contains 2.49 mol atoms of Nitrogen
1 mol ---- 6.02 *10²³ atoms
2.49 mol ----- 2.49*6.02*10²³ = 15.0*10²³ atoms of N</span>
Answer:
3
Explanation:
On the left side we have 3 Calcium atoms and 6 fluorine atoms
that means there need to be the same number on the right side
in the CaF2 molecules we already have 2 fluorine atoms so by multiplying with 3 we get 3 Ca and 6F
<span>0.0797 g
Looking at the formula, 1 mole of KIO3 and 5 moles of KI will react and produce moles of iodine molecules or 6 moles of iodine atoms. So first, determine the number of moles of KIO3 and KI provided
moles KIO3 = 0.0121 * 0.097 = 0.0011737 mol
moles KI = 0.0308 * 0.017 = 0.0005236 mol
The limiting reactant is KI at 0.0005236 mol so divide by 5 and multiply by 6 to get the number of moles of iodine atoms.
0.0005236 / 5 * 6 = 0.00062832 mol
Lookup the atomic weight of iodine which is 126.90447
And multiply that by the number of moles of iodine produced
126.90447 g/mol * 0.00062832 mol = 0.079736617 g
Rounding to 4 decimal places gives 0.0797 g</span>
Answer:The changes around us that involves chemistry is burning,cooking,rusting,and rotting.
Explanation:
