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ehidna [41]
3 years ago
8

Iron fluoride (FeF2) dissociates according to the following equation: FeF2(s) ⇌ Fe2+(aq) + 2 F–(aq) A sample of iron fluoride (F

eF2) is dissolved in water, and a saturated solution is obtained. The [Fe2+] is measured to be 2.05 × 10–4 mol/L. What is the concentration of fluoride (F–) ions?
Chemistry
1 answer:
Anastasy [175]3 years ago
6 0

Answer:

4.1 x 10^-4 mol/L

Explanation:

For the equation

FeF2(s)  --> Fe2+(aq) + 2F- (aq)

We have that for every mole of FeF2 we have a mole of Fe2+ and 2 moles of F-

FeF2(s)  --> Fe2+(aq) + 2F- (aq)

   1                  1                 2

If we have 2.05 x 10^-4 moles of Fe2+

FeF2(s)  --> Fe2+(aq) +      2F- (aq)

                2.05 x 10^-4         2 x 2.05 x 10^-4  

2 x 2.05 X 10^-4 = 5.1 x 10^-4 moles

So if in the solution is measured 2.05 x 10^-4 mol/L of [Fe2+] we have 5.1 x 10^-4 mol/L of [F-]

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The decomposition reaction of N2O5 in carbon tetrachloride is 2N2O5−→−4NO2+O2. The rate law is first order in N2O5. At 64 °C the
Mademuasel [1]

Answer:

(a) rate =  4.82 x 10⁻³s⁻¹  [N2O5]

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(c) rate =   2.32 x 10⁻⁴ M/s

(d) rate =   5.80 x 10⁻⁵ M/s

Explanation:  

We are told the rate law is first order in N₂O₅, and its rate constant is 4.82 x 10⁻³s⁻¹ . This means the rate is proportional to the molar concentration   of   N₂O₅, so

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(c) Since the reaction is first order if the concentration of  N₂O₅ is double the rate will double too:  2 x   1.16 x 10⁻⁴ M/s = 2.32 x 10⁻⁴ M/s

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Mass of Na₂S0₄.10H₂O = 322.24 g

Secondly, calculate mass of water present in hydrated compound. For this one should look for the coefficient present before H₂O in molecular formula of hydrated compound. In this case the coefficient is 10, so the mass of water is...

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Now, we will apply following formula to find percent of water in hydrated compound,

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Putting values,

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