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Harman [31]
2 years ago
7

Please help me due tonight

Mathematics
2 answers:
Svetlanka [38]2 years ago
8 0

Answer:

b.7\frac{2}{30}

Step-by-step explanation:

3\frac{2}{5}+3\frac{4}{6}\\=\frac{17}{5} +\frac{22}{6} \\=\frac{17*6}{5*6} +\frac{22*5}{6*5} \\=\frac{102}{30} +\frac{110}{30} \\=\frac{212}{30} \\=7\frac{2}{30}

Fittoniya [83]2 years ago
4 0

Answer:

7 1/15

Step-by-step explanation:

3 2/5 + 3 4/6 = 7 1/15

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ioda
I don't understand the question
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Which expression is a trinomial of degree 1?<br> A. x^3+x^2-x<br> B. xy^2<br> C. 6+x-y<br> D. 3x-y
ki77a [65]
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3 years ago
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Find a vector equation and parametric equations for the line through the point (1,0,6) and perpendicular to the plane x+3y+z=5.
tester [92]

The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.

Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:

(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)

This is the vector equation; getting the parametric form is just a matter of delineating

<em>x</em>(<em>t</em>) = 1 + <em>t</em>

<em>y</em>(<em>t</em>) = 3<em>t</em>

<em>z</em>(<em>t</em>) = 6 + <em>t</em>

5 0
2 years ago
Plot and connect the points A (2, -2), B (-4, -4), C (-4, -1), D (-2, 3), E (1, 3), F (2, 5), and find the length of BC.
Paul [167]

Answer:

BC = 3 units

Step-by-step explanation:

Given points:

  • A = (2, -2)
  • B = (-4, -4)
  • C = (-4, -1)
  • D = (-2, 3)
  • E = (1, 3)
  • F = (2, 5)

<u>Plot the points</u> on the coordinate plane (x, y) and connect them in alphabetical order with straight lines (see attached).

From visual inspection of the <u>drawn polygon</u>, we can see that the length of BC is 3 units.

It is fairly simple to calculate the length of BC without plotting the points.

As points B and C have the same x-value, this means that the distance between them is simply the difference between their y-values.

⇒ distance = |-4 - (-1)| = |-3| = 3 units

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2 years ago
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use the intermediate value theorem to determine whether the following equation has a solution or not x^3-3x-1
xxTIMURxx [149]

Answer:

Yes, this equation has a solution. According to Intermediate Value Theorem at least one solution for [0,2]

Step-by-step explanation:

Hi there!

1) Remember a definition.

Intermediate Value Theorem:

If f is continuous on a given closed interval [a,b], and f(a)≠f(b) and f(a)<k<f(b) then there has to be at least one number 'c' between 'a' and 'b', such that f(c)=k

----

(Check the first graph as an example)

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Let's choose the interval [0,2]

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Proceed to the other point: 2

f(x)=x^{3}-3x-1\\f(2)=(2)^{3}-3(2)-1\\f(2)=1\\f(2)>0\\

3) Check the 2nd Graph for a the Visual answer, of it.  And the 3rd graph for all solutions of this equation.

3 0
3 years ago
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