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arsen [322]
2 years ago
6

The Conway family is taking a photo at their family reunion. There are 2 chairs in the front row and 3 cousins who can sit in th

em. In how many ways can the cousins be arranged in the seats in the front row?
Mathematics
1 answer:
Serggg [28]2 years ago
5 0

Answer:

The answer is 6

Step-by-step explanation:

In the first chair, we have 3 people to choose from.

When it comes to the second chair, we now only have 2.

We can then multiply 3 x 2 to get 6 possible arrangements

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Factorise a³ - b³ + 4a-4b
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Answer:

a^3-b^3+4a-4b:\:\left(a-b\right)\left(a^2+ab+b^2+4\right)

Step-by-step explanation:

Given the expression

a^3-b^3+4a-4b

solving the expression

a^3-b^3+4a-4b

as

  • a^3-b^3

\mathrm{Apply\:Difference\:of\:Cubes\:Formula:\:}x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)

a^3-b^3=\left(a-b\right)\left(a^2+ab+b^2\right)

also

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\mathrm{Factor\:out\:common\:term\:}4

=4\left(a-b\right)

so the expression becomes

=\left(a-b\right)\left(a^2+ab+b^2\right)+4\left(a-b\right)

\mathrm{Factor\:out\:common\:term\:}\left(a-b\right)

=\left(a-b\right)\left(a^2+ab+b^2+4\right)

Therefore,

a^3-b^3+4a-4b:\:\left(a-b\right)\left(a^2+ab+b^2+4\right)

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Step-by-step explanation:

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