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elixir [45]
3 years ago
15

two submarines, one red and one blue, started rising toward the surface at the same time.they each rose at a constant speed. the

red submarine started rising from an altitude of 80 meters below the surface.after 30 seconds it was 60 meters below the surface.The following equation gives the altitude (in meters relative to the surface) of the blue submarine as a function of time (in seconds) A=-90+0.6t
Mathematics
1 answer:
Mnenie [13.5K]3 years ago
6 0

I NEED A BIT MORE DETAIL LOL

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How to solve quadratic inequalities.
Digiron [165]

Find all the zeros of the polynomial, and arrange the zeros in increasing order. ...

Plot those numbers on the number line as open or closed points based upon the original inequality symbol.

Choose a test value in each interval to see if the interval satisfies the inequality or not.

6 0
2 years ago
A roast turkey is taken from an oven when its temperature has reached 185 degrees F and is placed on a table in a room where the
Vedmedyk [2.9K]
(a) Using Newton's Law of Cooling, \dfrac{dT}{dt} = k(T - T_s), we have \dfrac{dT}{dt} = k(T - 75) where T is temperature after T minutes.
Separate by dividing both sides by T - 75 to get \dfrac{dT}{T - 75} = k dt. Integrate both sides to get \ln|T - 75| = kt + C.

Since T(0) = 185, we solve for C:
|185 - 75| = k(0) + C\ \Rightarrow\ C = \ln 110
So we get \ln|T - 75| = kt + \ln 110. Use T(30) = 150 to solve for k:
\ln| 150 - 75 | = 30k + \ln 110\ \Rightarrow\ \ln 75 - \ln 110= 30k \Rightarrow \\ k= \frac{1}{30}\ln (75/110) = \frac{1}{30}\ln(15/22)

So

\ln|T - 75| = kt + \ln 110 \Rightarrow |T - 75| = e^{kt + \ln110} \Rightarrow \\ \\
|T - 75| = 110e^{kt} \Rightarrow T - 75 = \pm110e^{(1/30)\ln(15/22)t}  \Rightarrow \\
T = 75 \pm110e^{(1/30)\ln(15/22)t}

But choose Positive because T > 75. Temp of turkey can't go under.

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} \\
T(45) = 75 + 110e^{(1/30)\ln(15/22)(45)}  = 136.929 \approx 137{}^{\circ}F

(b)

T(t) = 75 + 110e^{(1/30)\ln(15/22)t} = 75 + 110(15/22)^{t/30}  \\
100 = 75 + 110(15/22)^{t/30}   \\
25 = 110(15/22)^{t/30}  
\frac{25}{110} = (15/22)^{t/30}   \\
\ln(25/110) / ln(15/22) = t/30 \\
t = 30\ln(25/110) / ln(15/22)  \approx 116\ \mathrm{min}

Dogs of the AMS.
4 0
3 years ago
When estimating a job to bid, a contractor’s estimator first determines the actual cost of labor using the function L(h) = 28.75
dybincka [34]

Answer:

  M(h) = 73.18025h

Step-by-step explanation:

The composite function is ...

  M(B(L(h))) = M(B(28.75h)) = M(1.78(28.75h)) = M(51.175h)

  = 1.43(51.175h) = 73.18025h

The composite function is ...

  M(h) = M(B(L(h))) = 73.18025h

7 0
3 years ago
Solve the inequality 12(1/2x-1/3)>8-2x
gizmo_the_mogwai [7]

Answer:8(1/2x - 1/4)> 12 - 2x

a.x > 7

b.x > 7/3

c.x > 5/3

d.x > 5/3

Step-by-step explanation: Solve the inequality 12(1/2x-1/3)>8-2x

3 0
3 years ago
Draw 2 supplementary angles. One angle is x-15 degrees and one is 2x degrees. What is the value of x in degrees?
Bond [772]

Answer:

Step-by-step explanation:

Since they are supplementary, it means the addition of both angles gives 180 degree.

x - 15 + 2x = 180\\3x = 180 + 15\\3x = 195\\x = \frac{195}{3} \\x = 65

4 0
3 years ago
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