Which of the following choices is equivalent to -9x > -27?

Mathematics

2 answers:

sergey [27]2 years ago

7 0

$\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}$

<em>Which of the following is equivalent to -9x>-27?</em>

<em />

<em> </em> $\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}$

$\dagger$ First of all, we need to divide by -9 on both sides as follows:-

$\Large\bold{x < 3}$

$\dagger$ You may have noticed that the inequality sign changed from "greater than" to "less than".

$\bigstar$ This happened because we divided by a negative number on both sides.

<h3>Good luck with your studies.</h3>

$\rule{300}{1}$

Llana [10]2 years ago

5 0

Answer:

-9x>-27

x<-27/-9

x<3

note: the sign of the inequality will change if the equation is divided/multiplied by a negative number

example : -x<-3 (×-1)

x>3

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Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .