Both a transverse wave and a longitudinal wave have.

Which type of image is formed on a cinema screen?

Taya2010 [7]

Answer:

A real image is formed on a cinema screen.

Explanation:

It is a type of image that is formed when light rays coming from an object meet each other in actual after reflection or refraction. A real image can be easily obtained on the screen. It is always inverted

5 0

3 years ago

During an oil spill, oil coats the surface of the water, endangering sea life. Why doesn’t oil dissolve in ocean water? A)The li

djyliett [7]

D is the answer.........

3 0

3 years ago

Read 2 more answers

Which of the following may have happened if the inner planets had greater masses during the formation of the solar system? . . A

Svetach [21]

Right answer is option b that is the inner planet may havebeen larger and more gaseous.

5 0

3 years ago

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at rrr = 4.0 mm is πr

max2010maxim [7]

Complete Question

A spherical wave with a wavelength of 2.0 mm is emitted from the origin. At one instant of time, the phase at r_1 = 4.0 mm is π rad. At that instant, what is the phase at r_2 = 3.5 mm ? Express your answer to two significant figures and include the appropriate units.

Answer:

The phase at the second point is $\phi _2 = 1.57 \ rad$

Explanation:

From the question we are told that

The wavelength of the spherical wave is $\lambda = 2.0 \ mm = \frac{2}{1000} = 0.002 \ m$

The first radius is $r_1 = 4.0 \ mm = \frac{4}{1000} = 0.004 \ m$

The phase at that instant is $\phi _1 = \pi \ rad$

The second radius is $r_2 = 3.5 \ mm = \frac{3.5}{1000} = 0.0035 \ m$

Generally the phase difference is mathematically represented as

$\Delta \phi = \phi _2 - \phi _1$

this can also be expressed as

$\Delta \phi = \frac{2 \pi }{\lambda } (r_2 - r_1 )$

So we have that

$\phi _2 - \phi _1 = \frac{2 \pi }{\lambda } (r_2 - r_1 )$

substituting values

$\phi _2 - \pi = \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 )$

$\phi _2 = \frac{2 \pi }{0.002 } ( 0.0035 - 0.004 ) + 3.142$

$\phi _2 = 1.57 \ rad$

7 0

3 years ago

The Golden Gate Bridge in San Francisco has a main span of length 1.28 km, one of the longest in the world. Imagine that a steel

Valentin [98]

Answer:

361.46 N

Explanation:

$\alpha$ = Coefficient of thermal expansion = $11\times 10^{-6}\ /^{\circ}C$

Y = Young's modulus for steel = $20\times 10^{10}\ Pa$

A = Area = $3.1\times 10^{-6}\ m^2$

$L_0$ = Original length = 1.28 km

$\Delta T$ = Change in temperature = $45-(-10)$

Length contraction is given by

$\Delta L=\alpha L_0\Delta T$

Also,

$\Delta L=\dfrac{L_0T}{YA}$

$\alpha L_0\Delta T=\dfrac{L_0T}{YA}\\\Rightarrow T=\alpha \Delta TYA\\\Rightarrow T=11\times 10^{-6}\times (43-(-10))\times 20\times 10^{10} \times 3.1\times 10^{-6}\\\Rightarrow T=361.46\ N$

The tension in the wire is 361.46 N

4 0

3 years ago