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mojhsa [17]
3 years ago
11

A net force of 40 N south acts on an object with a mass of 20 kg. What is the

Physics
1 answer:
Murljashka [212]3 years ago
5 0

Answer:

B. 2m/s² south

Explanation:

Given parameters:

Net force  = 40N

Mass  = 20kg

Unknown:

Acceleration of the object = ?

Solution:

To solve this problem, we use;

            F = ma

F is the net force

m is the mass

a is the acceleration

          a  = \frac{f}{m}  

          a = \frac{40}{20}   = 2m/s²

The acceleration of the object is 2m/s² south

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Atmospheric conditions near a mountain range are such that a cloud at an altitude of 2.00 km contains 3.20 ✕ 10^7 kg of water va
kykrilka [37]

Answer:

time required is 6.72 years

Explanation:

Given data

mass m = 3.20 ✕ 10^7 kg

height h = 2.00 km = 2 × 10^3 m

power p = 2.96 kW  =2.96 × 10^3 J/s

to find out

time period

solution

we know work is mass × gravity force × height

and power is work / time

so we say that power =  mass  gravity force × height / time

now put all value and find time period

power =  mass × gravity force × height / time

2.96 × 10^3 =  3.20 ✕ 10^7  × 9.81× 2 × 10^3  / time

time =  62.784 × 10^10 / 2.96 × 10^3

time = 21.21081081 × 10^7 sec

time = 58.91891892 × 10^3 hours

time = 6.72 years

so time required is 6.72 years

3 0
3 years ago
Two capacitors of capacitances 25 µF and 50 µF are connected in series with a 33-V battery. How much energy is stored in the 25-
torisob [31]

Answer:

6.05×10⁻³ J

Explanation:

Note: Two capacitors connected in series behaves like two resistors connected in parallel.

Using

1/Ct = 1/C1+1/C2

Ct = (C1×C2)/(C1+C2)............................ Equation 1

Where Ct = combined capacitance of the two capacitor, C1 = Capacitance of the first capacitor, C2 = capacitance of the second capacitor.

Given: C1 = 25 µF, C2 = 50 µF

Substitute into equation 1

Ct = (25×50)/(25+50)

Ct = 1250/75

Ct = 16.67 µF.

Using

Q = CV.................... Equation 2

Where Q = Charge, V = Voltage.

Given: V = 33 V, C = 16.67 µF = 16.67×10⁻⁶ F

Substitute into equation 2

Q = 33(16.67×10⁻⁶)

Q = 5.5×10⁻⁴ C.

Since both capacitors are connected in series, the same amount of charge flows through them.

Using,

E = 1/2Q²/C.................. Equation 3

Where E = Energy stored in the 25-µF capacitor

Given: Q =5.5×10⁻⁴ C, C = 25 µF = 25×10⁻⁶ F

Substitute into equation 3

E = 1/2(5.5×10⁻⁴)²/ 25×10⁻⁶

E = 6.05×10⁻³ J.

5 0
4 years ago
All the interconnected paths of energy flowing from species to species in an ecosystem is called a
MAXImum [283]
D is the correct answer .
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4 years ago
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star a and star b have measured stellar parallax of 0.58 arc second and 0.73 arc second, respectively. which star is closer?
goldenfox [79]

Star B is closer than star A, because 1/ 0.58 = 1.72 pc, while 1/.73 = 1.36 pc.

<h3>What is stellar parallax and distance measurement using stellar parallax?</h3>

To calculate the distances to nearby stars, astronomers employ a phenomenon known as parallax. The apparent displacement of an object due to a change in the viewer's point of view is known as parallax. The distances between close stars can be calculated using this phenomenon. A nearer star will seem to move against the farther-off background stars as the Earth revolves around the Sun. By measuring a star's position once, then again six months later, astronomers can establish the apparent shift in location of that star. The apparent motion of the star is referred to as stellar parallax.

A straightforward correlation exists between the distance of a star and parallax angle:

d=\frac{1}{p}

The distance d and parallax angle p are both measured in parsecs and arcseconds, respectively.

Stellar parallax of star A= 0.58 arcseconds

Stellar parallax of star B= 0.73 arcseconds

So, on applying the formula,

The distance of the star A= 1.72pc

And the distance of the star B= 1.36pc

Therefore, star B is closer than star A.

To know more about stellar parallax, visit:

brainly.com/question/29352944

#SPJ4

3 0
1 year ago
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mafiozo [28]
Go on answers.com hope this helped give me brialinests since im the only one that helped and tell me when u did<span />
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