Answer:
x^4 + 8x
-----------------
(4-x^3)^2
Step-by-step explanation:
d /dx (x^2/(4-x^3))
When we differentiate a fraction u/v
df/dx = u/v
= v du/dx-u dv/dx
---------------------------
v^2
we know u = x^2 so du/dx = 2x
v = (4-x^3) so dv/dx = -3x^2
d dx = (4-x^3) (2x)- x^2 ( -3x^2)
-------------------------------------
(4-x^3)^2
Combining terms
(8x-2x^4) --3x^4
-------------------------------------
(4-x^3)^2
8x-2x^4 +3x^4
-------------------------------------
(4-x^3)^2
x^4 + 8x
-------------------------------------
(4-x^3)^2
Both triangles that are given (with right angles) lie in plane m, proving that AC is perpendicular to plane m. As angle acd is from a triangle that shares the common perpendicular, it too is a right angle
Let us model this problem with a polynomial function.
Let x = day number (1,2,3,4, ...)
Let y = number of creatures colled on day x.
Because we have 5 data points, we shall use a 4th order polynomial of the form
y = a₁x⁴ + a₂x³ + a₃x² + a₄x + a₅
Substitute x=1,2, ..., 5 into y(x) to obtain the matrix equation
| 1 1 1 1 1 | | a₁ | | 42 |
| 2⁴ 2³ 2² 2¹ 2⁰ | | a₂ | | 26 |
| 3⁴ 3³ 3² 3¹ 3⁰ | | a₃ | = | 61 |
| 4⁴ 4³ 4² 4¹ 4⁰ | | a₄ | | 65 |
| 5⁴ 5³ 5² 5¹ 5⁰ | | a₅ | | 56 |
When this matrix equation is solved in the calculator, we obtain
a₁ = 4.1667
a₂ = -55.3333
a₃ = 253.3333
a₄ = -451.1667
a₅ = 291.0000
Test the solution.
y(1) = 42
y(2) = 26
y(3) = 61
y(4) = 65
y(5) = 56
The average for 5 days is (42+26+61+65+56)/5 = 50.
If Kathy collected 53 creatures instead of 56 on day 5, the average becomes
(42+26+61+65+53)/5 = 49.4.
Now predict values for days 5,7,8.
y(6) = 152
y(7) = 571
y(8) = 1631
It will be 11v
If you rearrange it to 12v- v
Then it’ll look like 12v- 1v
Which equals 11v
