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Zepler [3.9K]
3 years ago
10

A _____________ exists between two variables when the values of one variable are somehow associated with the values of the other

variable.
a. difference
b. causation
c. inference
d. correlation
Mathematics
1 answer:
zysi [14]3 years ago
4 0

Answer:

Step-by-step explanation:

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What is the perimeter of the figure?
Zarrin [17]

Answer:

21.2 yd

Step-by-step explanation:

8 + 6 + 7.2 = 14 + 7.2 = 21.2

4 0
3 years ago
Read 2 more answers
Fredrick manages a band and sings lead vocals the band. Charges $700 per concert. Fredrick receives $175 of that money,and he sh
kodGreya [7K]

Answer:

$111

Step-by-step explanation

Subtract 700-175 and that leaves $555 to split equally so then divide $555 by 5 and youll get $111

6 0
4 years ago
Find an equation of a plane containing the line r=⟨0,4,4⟩+t⟨−3,−2,1⟩ which is parallel to the plane 1x−1y+1z=−5 in which the coe
ozzi

The plane you want is parallel to another plane, <em>x</em> - <em>y</em> + <em>z</em> = -5, so they share a normal vector. In this case, it's ⟨1, -1, 1⟩.

The plane must also pass through the point (0, 4, 4) since it contains <em>r</em><em>(t)</em>. Then the equation of the plane is

⟨<em>x</em>, <em>y</em> - 4, <em>z</em> - 4⟩ • ⟨1, -1, 1⟩ = 0

<em>x</em> - (<em>y</em> - 4) + (<em>z</em> - 4) = 0

<em>x</em> - <em>y</em> + <em>z</em> = 0

5 0
3 years ago
NEED ANSWERS AND EXPLANATION ASAP!!!
Elden [556K]

Answer:

see explanation

Step-by-step explanation:

(1)

Note the ratio of consecutive terms is common, that is

2000 ÷ 2500 = 0.8

1600 ÷ 2000 = 0.8

1280 ÷ 1600 = 0.8

This indicates that the series is geometric with common ratio r = 0.8

The sum to n terms of a geometric series is

S_{n} = \frac{a(1-r^n)}{1-r} ← a is the first term

Here a = 2500 and r = 0.8, thus

S_{5} = \frac{2500(1-0.8^5)}{1-0.8} = \frac{2500(0.67232)}{0.2} = 8404

(2)

Note the difference in consecutive terms is common, that is

3 - 11 = - 8

- 5 - 3 = - 8

- 13 - (- 5) = - 8

This indicates that the series is arithmetic with common difference d = - 8

The sum to n terms of an arithmetic series is

S_{n} = a₁ + (n - 1)d ← a₁ is the first term

Here a₁ = 11 and d = - 8, thus

S_{14} = 11 + (13 × - 8) = 11 - 104 = - 93

7 0
4 years ago
Can someone please help
laila [671]
B hope i helped (:::
6 0
3 years ago
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