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3 years ago

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A _____________ exists between two variables when the values of one variable are somehow associated with the values of the other

variable.
a. difference
b. causation
c. inference
d. correlation

1 answer:

zysi [14]3 years ago

4 0

Answer:

Step-by-step explanation:

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Please answer the following with Explaination

Zolol [24]

Step-by-step explanation:

brainliest plzz its confirm

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2 years ago

What is the square root

shusha [124]

Answer:

Step-by-step explanation:

Trying to factor as a Difference of Squares :

1.1 Factoring: r2-96

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 96 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step 1 :

r2 - 96 = 0

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : r2-96 = 0

Add 96 to both sides of the equation :

r2 = 96

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

r = ± √ 96

Can √ 96 be simplified ?

Yes! The prime factorization of 96 is

2•2•2•2•2•3

To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 96 = √ 2•2•2•2•2•3 =2•2•√ 6 =

± 4 • √ 6

The equation has two real solutions

These solutions are r = 4 • ± √6 = ± 9.7980

Two solutions were found :

r = 4 • ± √6 = ± 9.7980

Processing ends successfully

4 0

3 years ago

After the addition of an acid, a solution has a volume of 90 milliliters. The volume of the solution is 3 milliliters greater th

11111nata11111 [884]

Answer: $21.75\ milliliters$

Step-by-step explanation:

Let be "x" the original volume of the solution (in milliliters) before the acid was added and "y" the volume of the solution (in milliliters) after the addition of the acid.

Set up a system of equations:

$\left \{ {{x+y=90} \atop {y=3x+3}} \right.$

Applying the Substitution Method, you can substitute the second equation into the first equation and then solve for "x":

$x+y=90\\\\x+(3x+3)=90\\\\4x+3=90\\\\x=21.75$

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3 years ago

Solve the following system of equations. <br> 2x-5y=6<br> -2x+10y=-16<br> x=<br> y=

koban [17]

<span>x =<span>−<span><span>2<span> and </span></span>y </span></span></span>=<span>−<span>2. Hope this helps</span></span>

4 0

3 years ago

What would y=x^2 +x+ 2 be in vertex form

balu736 [363]

Answer:

$y = (x + \frac{1}{2} )^{2} + \frac{7}{4}$

Step-by-step explanation:

$y = {x}^{2} + x + 2$

We can covert the standard form into the vertex form by either using the formula, completing the square or with calculus.

$y = a(x - h)^{2} + k$

The following equation above is the vertex form of Quadratic Function.

<u>Vertex</u><u> </u><u>—</u><u> </u><u>Formula</u>

$h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{4a}$

We substitute the value of these terms from the standard form.

$y = a {x}^{2} + bx + c$

$h = - \frac{1}{2(1)} \\ h = - \frac{ 1}{2}$

Our h is - 1/2

$k = \frac{4(1)(2) - ( {1})^{2} }{4(1)} \\ k = \frac{8 - 1}{4} \\ k = \frac{7}{4}$

Our k is 7/4.

<u>Vertex</u><u> </u><u>—</u><u> </u><u>Calculus</u>

We can use differential or derivative to find the vertex as well.

$f(x) = a {x}^{n}$

Therefore our derivative of f(x) —

$f'(x) = n \times a {x}^{n - 1}$

From the standard form of the given equation.

$y = {x}^{2} + x + 2$

Differentiate the following equation. We can use the dy/dx symbol instead of f'(x) or y'

$f'(x) = (2 \times 1 {x}^{2 - 1} ) + (1 \times {x}^{1 - 1} ) + 0$

Any constants that are differentiated will automatically become 0.

$f'(x) = 2 {x}+ 1$

Then we substitute f'(x) = 0

$0 =2x + 1 \\ 2x + 1 = 0 \\ 2x = - 1 \\x = - \frac{1}{2}$

Because x = h. Therefore, h = - 1/2

Then substitute x = -1/2 in the function (not differentiated function)

$y = {x}^{2} + x + 2$

$y = ( - \frac{1}{2} )^{2} + ( - \frac{1}{2} ) + 2 \\ y = \frac{1}{4} - \frac{1}{2} + 2 \\ y = \frac{1}{4} - \frac{2}{4} + \frac{8}{4} \\ y = \frac{7}{4}$

Because y = k. Our k is 7/4.

From the vertex form, our vertex is at (h,k)

Therefore, substitute h = -1/2 and k = 7/4 in the equation.

$y = a {(x - h)}^{2} + k \\ y = (x - ( - \frac{1}{2} ))^{2} + \frac{7}{4} \\ y = (x + \frac{1}{2} )^{2} + \frac{7}{4}$

7 0

3 years ago