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son4ous [18]
3 years ago
13

I don't get this problem

Mathematics
1 answer:
DerKrebs [107]3 years ago
6 0

Answer:

22.2%

Step-by-step explanation:

Probability is the chance of an event happening, it can be found by using the following formula,

\frac{desired}{total}

Where the word (desired) represents the outcomes one wants, and (total) represents the total number of outcomes.

In this case, one is asked to find the probability of the sum of two numbers the results from rolling two dice, not being a multiple of (3) or (2). In this case, it is easier to list out the number of numbers between (1) and (12) that are not a multiple of three or two. Please note, the largest sum of number one can get when rolling two dice is (12), since the largest value on a dice is (6), and (6+6) equals (12).

Not multiples of (3) or (2):

1, 5, 7, 11

There are (4) numbers that are not multiples of (2) or (3). This means that there are (8) multiples of (2) or (3) between the numbers of (1) and (12), since (12 - 4 = 8)

The total number of outcomes is the following:

6^2=36

This is because there are (6) sides on a die, the number of outcomes is equal to (6) times (6), thus (6^2) or (36).

Now set up the probability equation:

\frac{desired}{total}

Substituted,

\frac{8}{36}

Write as a decimal:

0.222

As a percent:

22.2%

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Answer:

Probability that a randomly selected pregnancy lasts less than 233 ​days is 0.3594.

Step-by-step explanation:

We are given that the lengths of the pregnancies of a certain animal are approximately normally distributed with mean mu equals 238 days and standard deviation sigma equals 14 days.

Let X = <u><em>lengths of the pregnancies of a certain animal</em></u>

So, X ~ Normal(\mu=238,\sigma^{2} =14^{2})

The z score probability distribution for normal distribution is given by;

                         Z  =  \frac{X-\mu}{\sigma}  ~ N(0,1)

where, \mu = population mean = 238 days

           \sigma = standard deviation = 14 days

Now, the probability that a randomly selected pregnancy lasts less than 233 ​days is given by = P(X < 233 days)

   P(X < 233 days) = P( \frac{X-\mu}{\sigma} < \frac{233-238}{14} ) = P(Z < -0.36) = 1 - P(Z \leq 0.36)

                                                              = 1 - 0.6406 = 0.3594

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

4 0
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Answer:

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Option C

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If the recipe is for 1 gallon of sweat tea, then the cups of sugar needed is given as:

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so the receipe is for 3 gallon of sweet tea, then sugar needed is:

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Thus 4 cups of sugar is needed

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