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Helen [10]
2 years ago
10

Using division, select all the fractions that are equivalent to 30/40.

Mathematics
2 answers:
Mice21 [21]2 years ago
7 0

Answer:

3/4  6/8

Step-by-step explanation:

30/40 = .75

3/4= .75

6/8= .75

Mariulka [41]2 years ago
4 0

Answer:

The answer is C.) and E.)

Step-by-step explanation:

You might be interested in
31.24 to 1 decimal place
Blababa [14]

Answer:

31.2

Step-by-step explanation:

Because you only round up if the number next to the 1st decimal place is greater than 5, you just drop the 4 and keep 31.2.

6 0
3 years ago
14-2(x+8)=5x-(3x-34)
Scilla [17]

Answer:30=-34


Step-by-step explanation:

First you distribute so 2×X is 2X

2×8 is 16 then you do the other side but you put a one in front of the- so it goes 1 times 3x is 3x and you turn the minus into a plus sign and turn the positive 34 into a negative 34 so -34× 1 is -34 then write that out to look like 14-2X+16= 5X -3X + -34 then you add or subtract the commons which is 14+16= 30 and 5X-3X=2X so now your equation is 30-2x=2X+(-34) then you want to get your X on the same side so you subtract 2X from the right side and the left side then your left 30=-34

4 0
3 years ago
If one yard equals 3 ft in one mile equals 5280 ft how many yards are there in 2 miles
Georgia [21]

Answer:

2 miles = 3520 yards

Step-by-step explanation:

1 mile = 1760 yards

2 miles = 3520 yards

5 0
3 years ago
What is the answer to this word problem or how would I solve it
USPshnik [31]
Its a simultaneous equation:
lets make "x" the used games and "y" the new ones

4x + 2y = 84
6x + y = 78. (multiply this by 2 to cancel out y)
12x + 2y = 156

so now we subtract them:
12x - 4x = 156 - 84
x = 9
used games cost $9
new games cost 78 - 6(9) = $24

Janet has $120 but she already bought 3 NEW games so:
120 - 3(24) = $48 left

48/9 = how many used ones she can buy = 5. something

she can buy 5 used
5 0
3 years ago
This is due today, and I have no idea what I'm doing, please help if you know anything.
defon

Binomial distribution formula: P(x) = (n  k) p^k * (1 - p)^n - k

a) Probability that four parts are defective = 0.01374

P(4 defective) = (25 4) (0.04)^4 * (0.96)^21

P(4 defective) = 0.01374

b) Probability that at least one part is defective = 0.6396

Find the probability that 0 parts are defective and subtract that probability from 1.

P(0 defective) = (25 0) (0.04)^0 * (0.96)^25

P(0 defective) = 0.3604

1 - 0.3604 = 0.6396

c) Probability that 25 parts are defective = approximately 0

P(25 defective) = (25 25) (0.04)^25 * (0.96)^0

P(25 defective) = approximately 0

d) Probability that at most 1 part is defective = 0.7358

Find the probability that 0 and 1 parts are defective and add them together.

P(0 defective) = 0.3604 (from above)

P(1 defective) = (25 1) (0.04)^1 * (0.96)^24

P(1 defective) = 0.3754

P(at most 1 defective) = 0.3604 + 0.3754 = 0.7358

e) Mean = 1 | Standard Deviation = 0.9798

mean = n * p

mean = 25 * 0.04 = 1

stdev = \sqrt{np(1-p)}

stdev = \sqrt{(25)(0.04)(1-0.04)} = 0.9798

Hope this helps!! :)

7 0
3 years ago
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