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lakkis [162]
3 years ago
13

Fibonacci numbers can be found in many places in nature, for example, the number of petals in a daisy, the number of spirals in

a pine cone or a pineapple, and even the way branches grow on a tree. Find an example of something natural where you can see a Fibonacci number in action, and sketch it here.

Mathematics
1 answer:
Otrada [13]3 years ago
4 0

Answer: The Fibonacci sequence is a numerical pattern that can appear in many living things. It was first described in the 12th century by the Italian Leonardo Finonacci.

It is an infinite sequence that begins with 0 and 1. The sequence is completed with the sum of the previous 2 numbers.

Following this logic, we can assemble the sequence: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144 and so on.

This sequence is very common in nature and can be observed in many living things, such as insects, plants, the human face, even a chameleon's tail.

For example in a shell.

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Use explicit formula to find the 10th of each geometric sequence
Sindrei [870]

Answer:

1. 1*9^(10-1) = 387,420,489

2.2*4^(10-1) = 524,288

Step-by-step explanation:

The explicit formula for a geometric sequence is a1 * r^n-1

Where a1 is your first term, r is your ratio, and n is the amount of terms you want in the sequence

To solve for the 10th number in the sequence, we simply plug 10 in for n.

Hope this helps

3 0
2 years ago
Does y = x + 5 have one solution or an infinite number of solutions?​
Arlecino [84]

Answer:

infinite solution

Step-by-step explanation:

because it is a linear equation.

7 0
3 years ago
Find and simplify the quotient 2/3 divided by 8/9
Anuta_ua [19.1K]
The answer is 3/4 and it was already simplified
8 0
3 years ago
A programmer plans to develop a new software system. In planning for the operating system that he will​ use, he needs to estimat
Vedmedyk [2.9K]

Using the z-distribution, we have that:

a) A sample of 601 is needed.

b) A sample of 93 is needed.

c) A.  ​Yes, using the additional survey information from part​ (b) dramatically reduces the sample size.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

For this problem, we consider that we want it to be within 4%.

Item a:

  • The sample size is <u>n for which M = 0.04.</u>
  • There is no estimate, hence \pi = 0.5

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5(0.5)}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.5(0.5)}

\sqrt{n} = \frac{1.96\sqrt{0.5(0.5)}}{0.04}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.5(0.5)}}{0.04}\right)^2

n = 600.25

Rounding up:

A sample of 601 is needed.

Item b:

The estimate is \pi = 0.96, hence:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.96(0.04)}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.96(0.04)}

\sqrt{n} = \frac{1.96\sqrt{0.96(0.04)}}{0.04}

(\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.96(0.04)}}{0.04}\right)^2

n = 92.2

Rounding up:

A sample of 93 is needed.

Item c:

The closer the estimate is to \pi = 0.5, the larger the sample size needed, hence, the correct option is A.

For more on the z-distribution, you can check brainly.com/question/25404151  

8 0
2 years ago
Which statement best describes the function represented by the graph?
blondinia [14]

Answer:

The second one decreasing on the interval (-infinity, 0) where it becomes constant

4 0
3 years ago
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