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snow_tiger [21]
2 years ago
8

For one binomial experiment, n1 = 75 binomial trials produced r1 = 30 successes. For a second independent binomial experiment, n

2 = 100 binomial trials produced r2 = 50
successes. At the 5% level of significance, test the claim that the probabilities of success for the two binomial experiments differ.

(a) Compute the pooled probability of success for the two experiments. (Round your answer to three decimal places.)

(b)Compute the corresponding sample distribution value. (Test the difference p1 − p2. Do not use rounded values. Round your final answer to two decimal places.)

(c)Find the P-value of the sample test statistic. (Round your answer to four decimal places.)
Mathematics
1 answer:
Masja [62]2 years ago
7 0
The correct answer to your question would be B because it’s computea with the corresponding sample that distributes the value. welcome.
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Write the equation of the line in slope-intercept form that has the following points: (2, -1)(5, -3)
kirza4 [7]

Answer:

\large\boxed{y=-\dfrac{2}{3}x+\dfrac{1}{3}}

Step-by-step explanation:

The skope-intercept form:

y=mx+b

m - slope

b - y-intercept

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (2, -1) and (5, -3). Substitute:

m=\dfrac{-3-(-1)}{5-2}=\dfrac{-3+1}{3}=\dfrac{-2}{3}=-\dfrac{2}{3}

We have the equation:

y=-\dfrac{2}{3}x+b

Put the coordinates of the point (2 , -1) to the equation:

-1=-\dfrac{2}{3}(2)+b

-1=-\dfrac{4}{3}+b           <em>add 4/3 to both sides</em>

\dfrac{1}{3}=b\to b=\dfrac{1}{3}

Finally we have:

y=-\dfrac{2}{3}x+\dfrac{1}{3}

6 0
4 years ago
What is the probability of getting zero heads in six tosses? What is the probability of getting exactly two heads in six tosses?
alexira [117]

Answer:

The probability of getting zero heads in six tosses is 0.015625.

The probability of getting exactly two heads in six tosses is 0.234375.

Step-by-step explanation:

Using the Minitab software for computing the desired probabilities.

We take n=6 and p=1/2  because we have six tosses and in binomial distribution the probability of success p remains constant in each trial whereas the probability of success in this case is getting heads.

When a coin is tossed then there are two possible outcomes head or tail.

So,

p= P(heads)=1/2=0.5  

The probability of getting zero heads in six tosses is computed by considering the following steps:

In Minitab

Calc >Probability Distributions > Binomial

Select n=6 and p=0.5 and select input constant=0 and bubble the probability and by clicking OK we get the following output:

Probability Density Function  

Binomial with n = 6 and p = 0.5

x  P( X = x )

0    0.015625

So, the probability of getting zero heads in six tosses is 0.015625.

The probability of getting exactly two heads in six tosses is computed by considering the following steps :

In Minitab

Calc >Probability Distributions > Binomial

Select n=6 and p=0.5 and select input constant=2 and bubble the probability and by clicking OK we get the following output:

Probability Density Function  

Binomial with n = 6 and p = 0.5

x  P( X = x )

2    0.234375

So, the probability of getting exactly two heads in six tosses is 0.234375.

7 0
4 years ago
I’m failing my math class and I need help with math because I don’t understand some stuff.
lisov135 [29]
Then post the question(s)
6 0
3 years ago
Read 2 more answers
Danny made 84 cupcakes on Monday and n cupcakes on Tuesday. Which expression shows how many more cupcakes Danny made on Monday t
Veronika [31]

Answer:

84- n

A is the correct answer.

6 0
3 years ago
Select ALL the correct answers.
weeeeeb [17]

Answer:

(8,16) (0,22)  (10,10)

Step-by-step explanation:

Let x represents the number of hours spent volunteering in school and y represents the number of hours spent volunteering outside of school.  

Since each member must spend a minimum of 20 hours doing volunteer work each semester.

The equation forms : x+y\geq 20   ....(1)

Also given is that the number of hours spent volunteering at school activities can be no more than twice the number of hours spent volunteering outside of school, then  equation becomes:

x\leq 2y     .....(2)

So, lets check with each given pair, if they fulfill both equations:

(7,11): 7+11=18 is not ≥ 20  - This is false.

(15,6): 15 \leq 6(2) = 12 - This is false.

(8,16): 8+16=24 which is ≥20 and 8 \leq 2(16)=32 - This is true.

(12,5): 12 is not ≤ 2(5)=10 - This is false.

(0,22): 0+22\geq 20 and 0\leq 2(22)=44 - This is true.

(10,10): 10+10\geq 20 and 10\leq 2(10)=20- This is true.

6 0
4 years ago
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