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3241004551 [841]
2 years ago
12

Jordan and Sarah started cycling at the same time from the same place in opposite directions Jorans average speed was 16km per h

our. Sarah's average speed was 3 8/9m per second. both of them stopped cycling after 40 mins. How much further did Jordan cycle than Sarah? How far apart was Jordan from Sarah at the end of 40 mins?
pls have the right answer by tomorrow.
Mathematics
1 answer:
Afina-wow [57]2 years ago
5 0

Answer:

  • 1,333 1/3 m ≈ 1.33 km farther
  • 20 km separation

Step-by-step explanation:

The answer to this involves the relation between time, speed, and distance, as well as a couple of conversion factors.

  • distance = speed × time
  • 1 km = 1000 m
  • 1 h = 60 min
  • 1 min = 60 s

_____

<h3>Jordan's distance</h3>

Using the above conversion factors with Jordan's time and speed, we can find the distance Jordan traveled to be ...

  distance = speed × time

  distance = (16 km/h) × (40 min) = (16×1000 m)/(60 min) × (40 min)

  distance = 32000/3 m = 10,666 2/3 m

<h3>Sarah's distance</h3>

Using Sarah's time and speed, we find Sarah's distance to be ...

  distance = (3 8/9 m/s) × (40 min) × (60 s)/(1 min) = (3 8/9)(2400) m

  distance = 9333 1/3 m

__

<h3>difference</h3>

The difference between Jordan's distance and Sarah's is ...

  10,666 2/3 m -9,333 1/3 m = 1,333 1/3 m

Jordan cycled 1,333 1/3 meters farther than Sarah, about 1.33 km.

__

<h3>separation</h3>

The two went in opposite directions, so their separation is the sum of the distances they traveled.

  10,666 2/3 m +9,333 1/3 m = 20,000 m = 20 km

The two cyclists were 20 km apart at the end of 40 minutes.

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