Question

Practice Problems

Answer 1

(a) The acceleration of the salt shaker is 1.18 m/s².

(b) The distance traveled by the baseball player before coming to rest is 204.1 m.

Acceleration of the salt shaker

The acceleration of the salt shaker at the given coefficient of kinetic friction is determined as follows;

a = μg

a = 0.12 x 9.8

a = 1.18 m/s²

Acceleration of the baseball player is calculated as follows;

a = μg

a = 0.4 x 9.8

a = 3.92 m/s²

Distance traveled by the baseball player

The distance traveled by the baseball player before coming to rest is calculated as follows;

v² = u² - 2as

0 = 40² - 2(3.92)s

0 = 1600 - 7.84s

7.84s = 1600

s = 204.1 m

The complete question is below:

A baseball player slides into third base with an initial speed of 40 m/s. If the coefficient of kinetic friction between the player and the ground is 0.40, how far does the player slide before coming to rest?

Learn more about coefficient of friction here: brainly.com/question/20241845