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1 year ago

Practice Problems

Physics

1 answer:

vodomira [7]1 year ago

8 0

(a) The acceleration of the salt shaker is 1.18 m/s².

(b) The distance traveled by the baseball player before coming to rest is 204.1 m.

<h3>Acceleration of the salt shaker</h3>

The acceleration of the salt shaker at the given coefficient of kinetic friction is determined as follows;

a = μg

a = 0.12 x 9.8

a = 1.18 m/s²

Acceleration of the baseball player is calculated as follows;

a = μg

a = 0.4 x 9.8

a = 3.92 m/s²

<h3>Distance traveled by the baseball player</h3>

The distance traveled by the baseball player before coming to rest is calculated as follows;

v² = u² - 2as

0 = 40² - 2(3.92)s

0 = 1600 - 7.84s

7.84s = 1600

s = 204.1 m

The complete question is below:

A baseball player slides into third base with an initial speed of 40 m/s. If the coefficient of kinetic friction between the player and the ground is 0.40, how far does the player slide before coming to rest?

Learn more about coefficient of friction here: brainly.com/question/20241845

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