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hram777 [196]
3 years ago
8

Carter pushes a bag full of basketball jerseys across the gym floor. The he pushes with a constant force of 21 newtons. If he pu

shes the bag 9 meters in 3 seconds, how much power does he use?
Physics
2 answers:
Zolol [24]3 years ago
8 0
Carter needs a power equal to 63 W to be able to push the bag full of Jersey. This is by using the formula: Power is equal to the product of Force applied and Displacement all over time traveled.
Eva8 [605]3 years ago
4 0

Answer:

63 Watt

Explanation:

F = 21 N, s = 9 m, t = 3 s

Work done in pushing the bag, W = force x distance

W = 21 x 9 = 189 J

Power = work / time

P = 189 / 3 = 63 Watt

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What is meant by the statement that you don’t “own” the atoms that make up your body?
Zinaida [17]

Answer:

there are as many atoms in a normal breath of air as there are breathfuls of air in the atmosphere of the world

Explanation:

5 0
3 years ago
A car accelerates from rest at 1.0 m/s2 for 20.0 second along a straight road. It then moves at a constant speed for half an hou
Whitepunk [10]

Total distance = 36500 m

The average velocity = 19.73 m/s

<h3>Further explanation</h3>

Given

vo=initial velocity=0(from rest)

a=acceleration= 1 m/s²

t₁ = 20 s

t₂ = 0.5 hr = 1800 s

t₃= 30 s

Required

Total distance

Solution

State 1 : acceleration

\tt d=vo.t+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1\times 20^2\rightarrow vo=0\\\\d=200~m

\tt vt=vo+at\\\\vt=at\rightarrow vo=0\\\\vt=1\times 20\\\\vt=20~m/s

State 2 : constant speed

\tt d=v\times t\\\\d=20\times 1800\\\\d=36000~m

State 3 : deceleration

\tt vt=vo+at\rightarrow vt=0(stop)\\\\vo=-at\\\\20=-a.30~s\\\\a=-\dfrac{2}{3}m/s^2(negative=deceleration)

\tt d=vot+\dfrac{1}{2}at^2\\\\d=20.30-\dfrac{1}{2}.\dfrac{2}{3}.30^2\\\\d=300~m

Total distance : state 1+ state 2+state 3

\tt 200 + 36000 + 300=36500~m

the average velocity = total distance : total time

\tt avg~velocity=\dfrac{36500}{20~s+1800~s+30~s}=19.73~m/s

4 0
2 years ago
2. An athlete of average size is hanging from the end of a 20 m long rope, which has a mass of 4 kg and is attached to a hook in
a_sh-v [17]

Answer:

  t = 0.319 s

Explanation:

With the sudden movement of the athlete a pulse is formed that takes time to move along the rope, the speed of the rope is given by

             v = √T/λ

Linear density is

           λ = m / L

           λ = 4/20

           λ = 0.2 kg / m

The tension in the rope is equal to the athlete's weight, suppose it has a mass of m = 80 kg

           T = W = mg

           T = 80 9.8

           T = 784 N

The pulse rate is

          v = √(784 / 0.2)

          v = 62.6 m / s

The time it takes to reach the hook can be searched with kinematics

          v = x / t

          t = x / v

          t = 20 / 62.6

          t = 0.319 s

7 0
3 years ago
Considering this analogy (current = rate that heat flows through a window, and voltage = temperature difference across the windo
erastovalidia [21]

Answer:

Explained

Explanation:

Resistance R in a current flow through an object is given by

R= \frac{\rho L}{A}

ρ = resistivity of the material

L= length of the object

A=  area of cross section

clearly resistance is directly dependent on length of the object.This means greater the length larger will be resistance to current.

thermal resistance R_th is given by

R_{th} = \frac{L}{KA}

L= length of the object

A=  area of cross section

K = Conductivity of the material

thermal resistance is also is directly dependent on length of the object.This means greater the length larger will be resistance to current.

8 0
3 years ago
Read 2 more answers
Which element could be described by the list of properties above?
Murljashka [212]

Answer:  

list the properties

Explanation:

7 0
3 years ago
Read 2 more answers
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