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Sever21 [200]
1 year ago
14

Given two objects of the same mass but of different sizes, which object has a greater density?

Physics
1 answer:
wolverine [178]1 year ago
4 0

Given two objects of the same mass but of different sizes, the one that has a greater density is: a. the smaller object

Due to the density of an object is the relation that exist between the mass and the space that the object occupies, if we have two objects with the same mass the one that is going to have a greater density is the smaller object because it occupies less space with more mass.  

We can prove it using the density formula to solve the following exercise:

Two objects have a mass of  100 g, and their volume are 20 cm³ and 10 cm³ respectively, what is the density of each one?

The general formula of the density is:

d = m/v

Where:

  • d= density
  • m= mass
  • v= volume

Information about the problem:

  • m = 100 g
  • v1= 20 cm³
  • v2=10 cm³
  • d1=?
  • d2?

Applying the density  formula we get:

d = m/v

d1 = 100g/20 cm³

d1 = 5g/cm³

d2 = 100g/10 cm³

d2 = 10g/cm³

With the results we can confirm that the object that has the greater density is the smaller, because it has less volume.

<h3>What is density?</h3>

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

Learn more about density in: brainly.com/question/1354972

#SPJ4

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4 years ago
hree identical resistors are connected in series. When a certain potential difference is applied across the combination, the tot
pav-90 [236]

Answer:

The power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W

Explanation:

Given;

three identical resistors connected in series

let the first resistor = R₁

let the second resistor = R₂

let the third resistor = R₃

Rt = R₁ + R₂ + R₃

Since the resistors are identical, thus, R₁ = R₂ = R₃ = R

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Power is given as;

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P = \frac{V^2}{R_t} = \frac{V^2}{3R} \\\\3P = \frac{V^2}{R} ------equation(i)

If the 3 identical resistor connection were changed to parallel, then the equivalent resistance in the circuit will be;

\frac{1}{R_t} = \frac{1}{R_1} +\frac{1}{R_2} + \frac{1}{R_3} \\\\But, R_1 = R_2 = R_3\\\\\\frac{1}{R_t} = \frac{1}{R} +\frac{1}{R} + \frac{1}{R} \\\\\frac{1}{R_t} =\frac{3}{R} \\\\R_t = \frac{R}{3} \\\\P = \frac{V^2}{R_t} = \frac{3V^2}{R} \\\\P_{parallel} = \frac{3V^2}{R} ---------equation (ii)\\\\From \ equation \ (i), 3P_{series} = \frac{V^2}{R}, Substitute \ this \ into \ equation \ (ii)\\\\P = 3(\frac{V^2}{R} )\\\\P = 3(3P)\\\\P_{parallel} = 9P_{series}\\\\P_{parallel} = 9(45)\\\\

P_{parallel} = 405 \ W

Therefore, the power dissipated if the three resistors were connected in parallel across the same potential difference is 405 W

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4 years ago
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Otrada [13]
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Explanation:

5 0
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bearhunter [10]

Answer:

it's right you did a great job

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