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3 years ago

Which is developed during the process of technology design

Physics

1 answer:

Tatiana [17]3 years ago

4 0

Answer:

solution

Explanation:

A(n) __________ is developed during the process of technological design.

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How much force (in Newtons) is needed to accelerate a 160 kg object at a rate of 4 m/s2?

Klio2033 [76]

Answer:

C. 640

Explanation:

The minimum force would occur in a frictionless environment and act parallel to any abutting surface.

F = ma = 160(4) = 640 N

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2 years ago

the 120-lb woman jogs up the flight of stairsThe 120-lb woman jogs up the flight of stairs in 5 seconds. Determine her average p

Lera25 [3.4K]

Answer:

Power = 24.41Watts

Explanation:

Find the diagram attached

Power output = Force * distance/Time

Given

Force = 120lb

Distance = 9inches

Time = 5sec

Since

1lb = 4.4482216153 N

120lb = 120 * 4.4482216153

120lb = 533.787N

9in to meters

9in = 0.0254*9

9in = 0.2286N

Power = 533.787*0.2286/5

Power = 24.41Watts

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3 years ago

During the first 40 s a truck traveled at a constant speed of 15 m/s. Find the

kotykmax [81]

Answer:

600 m

Explanation:

Distance = speed × time

= (15)(40)

= 600 m

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3 years ago

A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1

Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) $I=0.0085\ A$

Explanation:

Given:

radius if the coil, $r=0.0395\ m$

no. of turns in the coil, $n=520$

variation of the magnetic field in the coil, $B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4$

resistor connected to the coil, $R=560\ \Omega$

(a)

we know, according to Faraday's Law:

$emf=n.\frac{d\phi}{dt}$

where:

$d \phi=$ change in associated magnetic flux

$\phi= B.A$

where:

A= area enclosed by the coil

Here

$A=\pi.r^2$

$A=\pi\times 0.0395^2$

$A=0.0049\ m^2$

$\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049$

So, emf:

$emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]$

$emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]$

$emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]$

$emf= 0.0306+3.516\times 10^{-4}\ t^3$

(b)

Given:

$t_0=5.25\ s$

Now, emf at given time:

$emf=4.7755\times 10^{-2}\ V$

∴Current

$I=\frac{emf}{R}$

$I=\frac{4.7755\times 10^{-2}}{560}$

$I=8.5\times 10^{-5} A$

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4 years ago

Over time people with aids become very sick and are unable to fight off infection

MaRussiya [10]

True. Their immune system weakens and they stay sick until they die.

5 0

4 years ago