Answer:
- 21.3 kJ
Explanation:
For the favorable reaction, ΔG₁ = + 9.2 kJ (ΔG > 0 for unfavorable reaction)
For the favorable reaction, ΔG₂ = - 30.5 kJ (ΔG < 0 for favorable reaction)
For the overall reaction, ΔG = ΔG₁ + ΔG₂ = + 9.2 kJ + (- 30.5 kJ)
ΔG = + 9.2 kJ - 30.5 kJ = - 21.3 kJ
Answer:
0 degrees
Explanation:
Let
are two forces. The resultant of two forces acting on the same point is given by :

Where
is the angle between two forces
When
i.e. when two forces are parallel to each other,


When
i.e. when two forces are parallel to each other,


When
i.e. when two forces are parallel to each other,


It is clear that the resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is 0 degrees. Hence, this is the required solution.
Answer:
A) C is 2 units towards right
B) C is 9 units towards right and 3 units towards up
C) C is 4 units towards right and 1 unit towards down
Explanation:
Drawings are given in the attachment.
A)Since,
A is 4 units towards right,
B is 1 unit towards left,
Then,
C is 2 units towards right.
B) Since,
A is 4 units towards right and 2 units towards up,
B is 1 unit towards left,
Then,
C is 9 units towards right and 3 units towards up.
C) Since,
A is 4 units towards right and 2 units towards up,
B is 1 unit towards right, and 1 unit towards down
Then,
C is 4 units towards right and 1 unit towards down.
Answer: Average Velocity = - 643.42 i + 512.66 j m/s
Magnitude = 822.7 m/s
Direction = 141.45°
Explanation:
r = 3.84 x 10^8 m
w = 2.46 x 10^-6 rad/s
Formula for Average velocity = displacement / time
at t = 0
x(0) = r
y(0) = 0
at t = 8.45 days
= 8.45 x 24 x 3600 s =730080 sec
w t = 2.46 x 10^-6 x 730080 = 1.80 rad Or 102.90°
xf = r cos(w t) = - 0.2233r
yf = r sin(w t) = 0.9747r
Displacement = (xf - x0)i + (yf - y0)j = -1.2233r i + 0.9747r j
<v> = dispalcement / t = (-1.2233r i + 0.9747r j ) / (730080 s )
= - 643.42 i + 512.66 j m/s
Magnitude
= sqrt(643.42^2 + 512.66^2)
= 822.7 m/s
Direction
= 180 - tan^-1(512.66 / 643.42)
= 141.45°
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