Answer:
The time interval is 
Explanation:
From the question we are told that
The angular acceleration is 
The time taken is 
The angular displacement is 
The angular displacement can be represented by the second equation of motion as shown below

where
is the initial velocity at the start of the 4 second interval
So substituting values

=> 
Now considering this motion starting from the start point (that is rest ) we have

Where
is the angular velocity at rest which is zero and
is the angular velocity after 4.0 second which is calculated as 12 rad/s s

=> 
Answer:
e see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1
Explanation:
This is an ejercise in special relativity, where the speed of light is constant.
Let's carefully analyze the approach, we see the two events at the same time.
The closest event time is
c = (x₁-300) / t
t = (x₁-300) / c
The time for the other event is
t = (x₂- 600) / c
since they tell us that we see the events simultaneously, we can equalize
(x₁ -300) / c = (x₂ -600) / c
x₁ = x₂ - 300
We see that the distances are different, the only way that the two beams of light approach simultaneously is that event 2 (farthest) occurs first than event 1
<span>If two wheels are exactly the same but spin at different speeds, wheel b is twice te speed of wheel a, it is possible to find the ratio of the magnitude of radial acceleration at a singular point of the rim on wheel be to the spot is four.</span>
The answer you have is right good job 12