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ludmilkaskok [199]
3 years ago
5

Which is developed during the process of technology design

Physics
1 answer:
Tatiana [17]3 years ago
4 0

Answer:

solution

Explanation:

A(n) __________ is developed during the process of technological design.

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In this section of a circuit, a current of 2.0 A flows across R1. What is the current across R2? Let R1 = 4.0 ohm, R2 = 8.0 ohm,
Liono4ka [1.6K]

Answer:

I=1A

Explanation:

In parallel combination voltage is same

In R1

V=IR

V=2×4

V=8V

In R2

V=IR

I=V/R

I=8/8

I=1A

3 0
4 years ago
what frequency of light must an electron in hydrogen absorb to jump from the n=2 state to the n=5 state? (a) 2.86 Hz (b) 4.08 Hz
Ostrovityanka [42]

Answer:

(c) 6.91x10^14 Hz

Explanation:

Find the level energy of n=2 and n=5, using  the formula:

E = -E_0/n^2

where  E_0=13.6eV

E_2 =\frac{-13.6}{2^2}=-3.4eV

E_5 =\frac{-13.6}{5^2}=-0.544eV

To jump from n=2 to n=5 the electron absorbs a photon with energy equal to (-0.544) - (-3.4)=2.856eV, using the next formula to find specific wavelength \lambda to that energy

E = hc/\lambda

Where c is the speed of light (c=3 \times10^8m/s) and h is Planck's constant (h=4.14\times10^{-15}eVs). Solve for \lambda:

E = hc/\lambda\\\lambda E = hc\\\lambda = \frac{hc}{E} \\\lambda = \frac{(4.14\times10^{-15})(3 \times10^8)}{2.856}=4.35\times10^{-7}m

The frequency of this wavelength is calculated with this formula:

f=\frac{c}{\lambda}

f=\frac{3\times10^8}{4.3487\times10^{-7}} =6.89\times10^{14}Hz\approx6.9\times10^{14}Hz

8 0
4 years ago
Find the ratio of the gravitational force between two planets if the masses of both planets are quadrupled but the distance betw
Snezhnost [94]

Answer:

The ratio of the new force over the original force is 16

Explanation:

Recall the formula for the gravitational force between two masses M1 and M2 separated a distance D:

F_G=G\,\frac{M_1\,\,M_2}{D^2}

So now, if the masses M1 and M2 are quadrupled and the distance stays the same, the new force becomes:

F'_G=G\,\frac{4M_1\,\,4M_2}{D^2}=G\,\frac{16\,\,M_1\,\,M_2}{D^2}=16\,\,G\,\frac{M_1\,\,M_2}{D^2}= 16\,\,F_G

which is 16 times the original force.

So the ratio of the new force over the original force is 16

5 0
3 years ago
What did Rutherford’s model of the atom include that Thomson’s model did not have?
Ksivusya [100]
Rutherford overturned Thomson's model in 1911 with his well-known gold foil experiment in which he demonstrated that the atom has a tiny and heavy nucleus. Rutherford designed an experiment to use the alpha particles emitted by a radioactive element as probes to the unseen world of atomic structure.
3 0
3 years ago
Mitochondria are responsible for
Inessa [10]
Breaking down energy into food
5 0
3 years ago
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