Answer:
2 real solutions
Step-by-step explanation:
Given a quadratic equation in standard form
ax² + bx + c = 0 ( a ≠ 0 ), then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct solutions
• If b² - 4ac = 0 then 2 real and equal solutions
• If b² - 4ac < 0 then no real solutions
x² + 4x - 3 = 0 ← is in standard form
with a = 1, b = 4, c = - 3 , then
b² - 4ac = 4² - (4× 1 × - 3) = 16 - (- 12) = 16 + 12 = 28
Since b² - 4ac > 0 then the equation has 2 real and distinct solutions
For the first part
5 an hour plus 50
Can you make an equation out of it
Answer:
3/17
Step-by-step explanation:
-2x + 3(-5x + 1)
-2x -15x +3
-17x + 3
17x = 3
x = 3/17
Step-by-step explanation:
Use triangle congruency:
BC=EC, AC=DC - Given
m∠DCE = m∠ACB because they are vertical angles
Therefore ΔABC ≅ ΔDEC because of Side-Angle-Side congruency
AB=DE because corresponding parts of congruent triangles are also congruent (CPCTC)
