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Vilka [71]
2 years ago
12

Identify the zeros of the graphed function.

Mathematics
2 answers:
Sever21 [200]2 years ago
6 0

Answer:

A I think this is it

Step-by-step explanation:

Hope this helps :) :)

Andrew [12]2 years ago
5 0
The answer is C
explanation
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amal says that 1/4 of rectangle is shaded, cadence says that 1/2 of rectangle is shaded, Jim says that 1 rectangle is shaded. de
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Each student used a rectangle<span />
3 0
3 years ago
Simplify (-343,000) 1/3
bixtya [17]
-343,000 x 1/3 = -114,333.333333333219
3 0
2 years ago
Solve for x and graph the solution on the number line<br> 15 &gt; 2x – 9 &gt; -23
Monica [59]

The answer is 12>x>-7

Step-by-step explanation:

it's first divided into 2 parts

1 . 15 > 2x - 9

2. 2x - 9 > -23

Then solve them individually.

let's do it,

<u>First half</u>

15 > 2x - 9

15+9 > 2x

24 > 2x

24/2 > x

12>x

<u>Second half</u>

2x-9>-23

2x>-23+9

2x>-14

x>-14/2

x>-7

<u>Joining of the two halves</u>

We have :

12>x>-7

8 0
3 years ago
Come graphs find the value of h,k, or a
TEA [102]

Answers:

  • Translation 3 units up
  • k = 3

============================================================

Explanation:

The y intercept of the black f(x) curve is at (0,1)

The y intercept of the blue curve is at (0,4)

To go from y = 1 to y = 4, we add 3

So we shift 3 units up to go from the f(x) curve to the g(x) curve.

The value of k is 3, which corresponds exactly to the vertical shift. If we shifted down, then k would be negative.

8 0
3 years ago
The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w
dimulka [17.4K]

Answer:

99% CI:

-4.637\leq\mu_v-\mu_o\leq 3.737

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

s_{Md}=\sqrt{\frac{2MSE}{n_h}}

The MSE can be calculated as

MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65

The weighted sample size nh can be calculated as

n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16

The standard deviation then becomes

s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

\Delta M=M_v-M_o=5.10-5.55=-0.45

Then the confidence interval can be constructed as

\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737

8 0
3 years ago
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