Hello,
The median of the temperatures at Springwood is 86. (median is at the middle).
the median of the temperatures at Meadows is 73. (median is at the middle).
The (IQR) interquartile range of the temperatures at Meadows is 12. (You have to subtract both of the IQR left and right 80 - 68 = 12).
The (IQR) interquartile range of the temperatures at Springwood is 14. (You have to subtract both of the IQR left and right 91 - 77 = 14).
the difference of the medians as a multiple of their average interquartile range is 79.5 is average median and 13 average IQR.
Answer:
See below
Step-by-step explanation:
Your question is a bit unclear, so I'm going to assume you want the value of y or x:
(y+3)^2=-12(x-2)
-(y+3)^2/12=x-2
-(y+3)^2/12+2=x
(y+3)^2=-12(x-2)
y+3=sqrt(-12x+24)
y=sqrt(-12x+24)-3
9y - 4x - 9 = 0
9y = 4x + 9
y = 4/9x + 1
f(x) = 4/9x + 1
