Answer: D
<u>Step-by-step explanation:</u>
The first matrix contains the coefficients of the x- and y- values for both equations (top row is the top equation and the bottom row is the bottom equation. The second matrix contains what each equation is equal to.
![\begin{array}{c}2x-y\\x-6y\end{array}\qquad \rightarrow \qquad \left[\begin{array}{cc}2&-1\\1&-6\end{array}\right] \\\\\\\begin{array}{c}-6\\13\end{array}\qquad \rightarrow \qquad \left[\begin{array}{c}-6\\13\end{array}\right]](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bc%7D2x-y%5C%5Cx-6y%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-1%5C%5C1%26-6%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%5C%5C%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cqquad%20%5Crightarrow%20%5Cqquad%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D-6%5C%5C13%5Cend%7Barray%7D%5Cright%5D)
The product will result in the solution for the x- and y-values of the system.
Answer:
Step-by-step explanation:
I fu-ck-ed my girl-friend real good
Answer:
134 children and 120 adult plates were served
Step-by-step explanation:
let the children mean be x
Let the adult meal be y
If fourteen less children’s meals were served than adult meals at a barbecue, then;
y = x - 14 .... 1
IF Children plate were 1.50 each and adult plates were 2.00 each with a total of 441 in amount then;
1.5x + 2y = 441 .... 2
Substitute 1 into 2;
1.5x + 2(x-14) = 441
1.5x+2x-28 = 441
3.5x = 441+28
3.5x = 469
x = 469/3.5
x = 134
Recall that y = x - 14
y = 134-14
y = 120
Hence 134 children and 120 adult plates were served
Answer:
*3545*
Step-by-step explanation:
52 square + 29 square = 3545
then square root 3545 = 59.539 ( round it if you want)
