Answer:
113.58 m
Explanation:
Range = Maximum Height
tan θ = 4
θ = 76 degree
Let u be the velocity of projection
K = 1/2 x m x u^2
1150 = 0.5 x 0.97 x u^2
u = 48.7 m/s
Range = [tex]\frac{u^{2}Sin2\theta }{g}
R = (48.7 x 48.7 x 2 x Sin 76 x Cos 76) / 9.8 = 113.58 m
A = horizontal displacement of the humming bird = 1.2 m
B = vertical displacement of the humming bird = 1.4 m
C = net displacement of the humming bird from initial to final position = ?
In the triangle drawn , Using Pythagorean theorem
C = √(A² + B²)
inserting the values
C = √(1.2² + 1.4²)
C = √(1.44 + 1.96)
C = √(3.4)
C = 1.4 m
Hence the net displacement of hummingbird comes out to be 1.4 m
