Answer:
he peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.
Explanation:
In a resonance experiment, the amplitude of the system is plotted as a function of the frequency, finding maximums for the values where some natural frequency of the system coincides with the excitation frequency.
In a Fourier transform spectrum, the amplitude of the frequencies present is the signal, whereby each peak corresponds to a natural frequency of the system.
From this explanation we can see that in the first case the peaks are the natural frequencies that coincide with the excitation frequencies and in the second case they are the natural frequencies that make up the wave.
Answer:
Three long wires are connected to a meter stick and hang down freely. Wire 1 hangs from the 50-cm mark at the center of the meter stick and carries 1.50 A of current upward. Wire 2 hangs from the 70-cm mark and carries 4.00 A of current downward. Wire 3 is to be attached to the meterstick and to carry a specific current, and we want to attach it at a location that results ineach wire experiencing no net force.
(a) Determine the position of wire 3.
b) Determine the magnitude and direction of current in wire 3
Explanation:
a) ![F_{net} \text {on wire }3=0](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%5Ctext%20%7Bon%20wire%20%7D3%3D0)
![\frac{\mu_0 I_1 I_3}{2 \pi x} = \frac{\mu I_2 I_3}{2 \pi (0.2+x)} \\\\\frac{1.5}{x} =\frac{4}{0.2+x} \\\\0.03+1.5x=4x\\\\x=0.012m\\\\=1.2cm](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmu_0%20I_1%20I_3%7D%7B2%20%5Cpi%20x%7D%20%3D%20%5Cfrac%7B%5Cmu%20I_2%20I_3%7D%7B2%20%5Cpi%20%280.2%2Bx%29%7D%20%5C%5C%5C%5C%5Cfrac%7B1.5%7D%7Bx%7D%20%3D%5Cfrac%7B4%7D%7B0.2%2Bx%7D%20%5C%5C%5C%5C0.03%2B1.5x%3D4x%5C%5C%5C%5Cx%3D0.012m%5C%5C%5C%5C%3D1.2cm)
position of wire = 50 - 1.2
= 48.8cm
b) ![F_{net} \text {on wire }1=0](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%5Ctext%20%7Bon%20wire%20%7D1%3D0)
![\frac{\mu _0 I_1 I_3}{2 \pi (1.2)} = \frac{\mu _0 I_1 I_2}{2 \pi (20)} \\\\\frac{I_3}{1.2} =\frac{4}{20} \\\\I_3=0.24A](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmu%20_0%20I_1%20I_3%7D%7B2%20%5Cpi%20%281.2%29%7D%20%3D%20%5Cfrac%7B%5Cmu%20_0%20I_1%20I_2%7D%7B2%20%5Cpi%20%2820%29%7D%20%5C%5C%5C%5C%5Cfrac%7BI_3%7D%7B1.2%7D%20%3D%5Cfrac%7B4%7D%7B20%7D%20%5C%5C%5C%5CI_3%3D0.24A)
Direction ⇒ downward
Answer:
Dear Kaleb
Answer to your query is provided below
Acceleration of the vehicle is 12m/s^2
Explanation:
Explanation for the same is attached in image
Answer:
970.2 N
Explanation:
We are given that
Length of ladder=2.7 m
Mass,M=11 kg
Coefficient of friction=![\mu=0.45](https://tex.z-dn.net/?f=%5Cmu%3D0.45)
![\theta=51^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D51%5E%7B%5Ccirc%7D)
Mass of painter=8M
Distance from base=d
We have to find the magnitude of the normal force exerted by the floor on the ladder.
Normal force exerted by floor on the ladder=![mg+8mg=9mg](https://tex.z-dn.net/?f=mg%2B8mg%3D9mg)
Where ![g=9.8m/s^2](https://tex.z-dn.net/?f=g%3D9.8m%2Fs%5E2)
Normal force exerted by floor on the ladder=![9\times 11\times 9.8=970.2N](https://tex.z-dn.net/?f=9%5Ctimes%2011%5Ctimes%209.8%3D970.2N)
<span>Surface ocean currents are generally wind-driven. However, the rotation of the Earth affects the way the waters move through currents. Without rotation, currents may not exist.</span>