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Paraphin [41]
3 years ago
5

A long, fine wire is wound into a coil with inductance 5 mH. The coil is connected across the terminals of a battery, and the cu

rrent is measured a few seconds after the connection is made. The wire is unwound and wound again into a different coil with L = 10 mH. This second coil is connected across the same battery, and the current is measured in the same way. Compared with the current in the first coil, is the current in the second coil. ( Select all of them that applies)A- Twice as largeB- One-Fourth as largeC- UnchargedD- Half as largeE- Four times as large
Physics
2 answers:
Allisa [31]3 years ago
5 0

Answer:

unchanged

Explanation:

Let the voltage of the battery be V

Inductance L1 = 5 mH

Inductance L2 = 10 mH

consider resistance R of the circuit (wire, battery).

V = I R + L dI/dt

where, I is the current in the circuit and t is the time.

After few seconds of connection being made, the factor dI/dt is negligible. There is no change in the current flowing through the circuit. when inductor was just attached in the circuit, a current

Rom4ik [11]3 years ago
5 0

Answer:

Explanation:

The self inductance of the solenoid depends on the number f turns in the coil. As the battery remains same so the current remains same, but the number of turns changed so that the self inductance is changed.

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A string along which waves can travel is 4.36 m long and has a mass of 222 g. The tension in the string is 60.0 N. What must be
lora16 [44]

Answer:

frequency is 195.467 Hz

Explanation:

given data

length L = 4.36 m

mass m = 222 g = 0.222 kg

tension T = 60 N

amplitude A = 6.43 mm = 6.43 × 10^{-3} m

power P = 54 W

to find out

frequency f

solution

first we find here density of string that is

density ( μ )= m/L ................1

μ = 0.222 / 4.36  

density μ is 0.050 kg/m

and speed of travelling wave

speed v = √(T/μ)       ...............2

speed v = √(60/0.050)

speed v = 34.64 m/s

and we find wavelength by power that is

power = μ×A²×ω²×v  /  2     ....................3

here ω is wavelength put value

54 = ( 0.050 ×(6.43 × 10^{-3})²×ω²× 34.64 )   /  2

0.050 ×(6.43 × 10^{-3})²×ω²× 34.64 = 108

ω² = 108 / 7.160  × 10^{-5}

ω = 1228.16 rad/s

so frequency will be

frequency = ω / 2π

frequency = 1228.16 / 2π

frequency is 195.467 Hz

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3 years ago
Give me 1 example of complete inelastic collision​
Allisa [31]

i hope it helped thanks

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Why do the passengers on a high-flying airplane not appear weightless, similar to the astronauts on the space station?
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