Answer:
it changes by taking the air from below the plane and curving it to the top causing draw wich slows it down then the weight that pulls it down to land.
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Explanation:
Answer:
You can create a new K.M.S key and use it to allow cryptographic assistants using AWS key management to store and encrypt sensitive information.
Explanation:
K.M.S is a computational model that covers more than one server on a local network, which has the power to automatically activate a set of computers that are in the same location and connected to the same network. In summary, a K.M.S key can act as a windows activation server. When a computer is activated by a K.M.S activation key, it will need to be reconnected to a K.M.S host twice a year to renew its activation. This can be very useful for the security of both files and the machine itself.
Regarding the question above, a K.M.S key is the ideal system to be used if you want to protect some information and want to prevent other developers on your team or anyone from seeing your credentials in plain text. To do this, you must create a new K.M.S key and use it to allow cryptographic assistants who use or manage AWS keys to store and encrypt as confidential information.
We have to find the resistance.
V = 12
A = 2
R = ?
And then we divide it to find r.
12/2 = 6 ohm's.
Answer:
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
Explanation:
At first we present a figure describing the situation explained on statement, the x and y components of the force are determined by the following trigonometric expressions:
(1)
(2)
Where:
- Magnitude of the force, measured in newtons.
- Direction of the force above the horizontal surface, measured in sexagesimal degrees.
If we know that 
and 
, then the components of the force is:
The x and y components of the 500 N-force are 321.394 newtons and 383.023 newtons, respectively.
Answer:
Explanation:
As we know that ball travels horizontal distance of 24.7 m with uniform speed 49.4 m/s
so we will have
now in the same time ball is turned by angle
now we know that
now the tangential speed of a point at equator is given as
