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galben [10]
3 years ago
14

For the following elementary reaction 2br• -> br2-. The rate of consumption of the reaction and the rate of formation of prod

uct is given by which set of expression? ​

Physics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer: -\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

2Br^.\rightarrow Br_2

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{d[Br^.]}{2dt}

or Rate=+\frac{d[Br_2]}{dt}

Thus -\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}

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A motorcycle starts from rest and has a constant acceleration. In a time interval t, it undergoes a displacement x and attains a
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Answer:

√(6ax)

Explanation:

Hi!

The question states that during a time t the motorcyle underwent a displacement x at constant acceleration a starting from rest, mathematically we can express it as:

x=(1/2)at^2

Then the we need to find the time t' for which the displacement is 3x

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Read 2 more answers
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