1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
galben [10]
3 years ago
14

For the following elementary reaction 2br• -> br2-. The rate of consumption of the reaction and the rate of formation of prod

uct is given by which set of expression? ​

Physics
1 answer:
Scorpion4ik [409]3 years ago
4 0

Answer: -\frac{1}{2}\times \frac{d[Br^.]}{dt}=+\frac{d[Br_2]}{dt}

Explanation:

Rate of a reaction is defined as the rate of change of concentration per unit time.

Thus for reaction:

2Br^.\rightarrow Br_2

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Rate=-\frac{d[Br^.]}{2dt}

or Rate=+\frac{d[Br_2]}{dt}

Thus -\frac{d[Br^.]}{2dt}=+\frac{d[Br_2]}{dt}

You might be interested in
Plzzzzz help me swear will mark u brainiest
photoshop1234 [79]

Answer:

B

Explanation:

4 0
3 years ago
Read 2 more answers
What is the current in a wire of radius R = 2.02 mm if the magnitude of the current density is given by (a) Ja = J0r/R and (b) J
Sloan [31]

Explanation:

For this problem we have to take into account the expression

J = I/area = I/(π*r^(2))

By taking I we have

I = π*r^(2)*J

(a)

For Ja = J0r/R the current is not constant in the wire. Hence

I(r) = \pi r^{2} J(r) = \pi r^{2} J_{0}r/R = \pi r^{3} (3.74*10^{4}A/m^{2})/(2.02*10^{-3}m)

and on the surface the current is

I(R) = \pi r^{2} J(R) = \pi r^{2} J_{0}R/R = \pi(2.02*10^{-3})^{2} (3.74*10^{4}) = 0.47 A

(b)

For Jb = J0(1 - r/R)

I(r)=\pi r^{2}J(r) =\pi r^{2} J_{0}(1 - r/R)=\pi r^{2}J_{0}(1-\frac{r}{2.02*10^{-3}} )

and on the surface

I(R)=\pi r^{2}J_{0}(1-R/R)=\pi r^{2}J_{0}(1-1)= 0

(c)

Ja maximizes the current density near the wire's surface

Additional point

The total current in the wire is obtained by integrating

I_{T}=\pi\int\limits^R_0 {r^{2}Ja(r)} \, dr = \pi \frac{J_{0}}{R}\int\limits^R_0 {r^{3}} \ dr =\pi  \frac{J_{0}R^{4}}{4R}=\frac{1}{4}\pi J_{0}R^{3}=2.42*10^{-4} A

and in a simmilar way for Jb

I_{T}=\pi J_{0} \int\limits^R_0 {r^{2}(1-r/R)} \, dr = \pi   J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2R}]=\pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2}]

And it is only necessary to replace J0 and R.

I hope this is useful for you

regards

7 0
3 years ago
Write the type of simple machine shown in the diagram gn the line by its number.
Elanso [62]
2. Wheel and axle
3.fulcrum
6.wheel and axle (I think) hope this helps!
7 0
2 years ago
Help me please with science
Simora [160]

Answer:its b

Explanation:

8 0
3 years ago
A 2MeV proton is moving perpendicular to a uniform magnetic field of 2.5 T.the force on a proton is
Snowcat [4.5K]

Answer:

7.8x10-12N

Explanation:

We know that

Magnetic force = F = qVB

And

Also Kinetic energy K.E is

E = (1/2)mV²

So making v subject

V = √(2E / m)

And

E = KE = 2MeV

= 2 × 106 eV

= 2 × 106 × 1.6 × 10–19 J

= 3.2 × 10–13 J

And then

V= √2x3.2E-13/1.6E-27

1.9E7m/s

Given that

mass of proton = 1.6 × 10–27 kg,

Magnetic field strength B = 2.5 T.

So F= qBv sinစ

=

So F = 1.6 × 10–19 × 2.5 × 1.9 x10^7 x sin 90°

= 7.8 x 10^-12N

5 0
3 years ago
Read 2 more answers
Other questions:
  • What kind of scientist investigation involve making observations
    10·2 answers
  • Rocks A and B are located at the same height on top of a hill. The mass of rock A is twice the mass of rock B. How does the pote
    8·1 answer
  • Nasa has developed deep-space 1 (ds-1), a spacecraft that is scheduled to rendezvous with the asteroid named 1992 kd (which orbi
    8·1 answer
  • A 10-g bullet moving horizontally with a speed of 2.0 km/s strikes and passes through a 4.0-kg block moving with a speed of 4.2
    7·1 answer
  • A person's prescription for his new bifocal eyeglasses calls for a refractive power of -0.0675 diopters in the distance-vision p
    6·1 answer
  • Descending into earth’s interior, temperature, as well as pressure on rock, _____.
    9·2 answers
  • I SEE YOU....STOO CHEATING!!!!!!
    9·1 answer
  • A sample of oxygen gas occupies a volume of 5.0L at 90kPa pressure. What volume will it occupy at 145kPa?
    12·1 answer
  • What are two ways in which ultrasound technology produces images
    12·1 answer
  • A small oil droplet is sprayed between the plates of a parallel plate capacitor. The droplet has a net charge equal to that of 3
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!