(T 4 Marks + C 1 Marks)

Mathematics

1 answer:

bija089 [108]3 years ago

4 0

Answer:

<h2>length= 40cm</h2><h2>width= 120cm</h2><h2>Step-by-step explanation:</h2>

Area of a rectangle= lenght× width

Dimensions of 1st rectangle: L,W

Dimensions of 2nd rectangle: L+10; W+4

Hence,

LW = 480__________(1)

(L-10)(W+4) = 480_______(2)

LW = LW+4L - 10W - 40

4L = 10W +40

2L = 5W + 20

L = (5/2)W + 10_________(3)

But LW = 480 (from equation one)

So, W = 480/L

substitute as= 480/L into equation (3)

L = (5/2)(480/L)+10

L = 1200/L + 10

L^2 - 10L - 1200 = 0

factorising.

we're have,

(L-40)(L+30) = 0

therefore, since L can't be negative , L = 40

L = 40 cm (length)

Then 480/L = W = 120 cm (width)

<h2>therefore L= 40cm and W= 120cm</h2>

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Determine the value of "L"

saveliy_v [14]

Opposite sides equals to 7 and so you add 7 + 7 which equals to 14. Next you subtract 30 by 14 to get the total of the opposite side of L and itself which gets you 16 which is then divided by 2 because you have L and its opposite side which would give you 8. So L equals to 8.

Check:

7 + 7 + 8 + 8

14 + 16

7 0

4 years ago

Please help and show your work for both a. and b.

bixtya [17]

Answer:

C = 5/8 (F - 32)

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