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ArbitrLikvidat [17]
2 years ago
7

PLEASE HELP I WILL BRAINLIEST !

Mathematics
1 answer:
jasenka [17]2 years ago
8 0

Answer:

10 1/12

Step-by-step explanation:

In order to subtract fractions, you have to give them a common denominator.

18 1/2 can be rewritten as 18 6/12, as they are the same thing and 6/12 simplifies to 1/2. We make it 6/12 because we have to subtract it by 8 5/12, and the denominators are both 12.

So now we have 18 6/12 - 8 5/12, which gives us 10 1/12.

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A barometer falls from a weather balloon
8_murik_8 [283]

Answer:

Step-by-step explanation:

h(t) = -16t² + 14400

0= -16t² + 14400

(1/-16)×-14400=-16t²(1/-16)

900=t²

\sqrt{900} =\sqrt{t^{2}}

30=t

7 0
2 years ago
PLEASE HELP ASAP!!!!!!!!!!!!!!!!!!!!!!!!!
ollegr [7]

Answer: For 1 it is A - f(x)=(x-2)(x+4) and for 2 it is C - y = 0.5x^2 + 1.5x − 5

Step-by-step explanation:

Just use Desmos

7 0
1 year ago
Write an equivalent expression by distributing the
melamori03 [73]

Answer:

-8m + (-7.7n - 6)

Step-by-step explanation:

You distribute the negative in front of the parentheses, to everything inside of the parentheses, and change the sign to addition.

7 0
3 years ago
What is the solution to x=1/2y-3 and y=2x+6
Tom [10]

Answer:

infinite solutions

Step-by-step explanation:

Multiply the first equation by 2 so we don't have fractions.

x = 1/2y - 3 becomes 2x = y - 6

Now substitute the second equation into the y-value of the new equation

2x = (2x + 6) - 6

2x = 2x

x can equal anything. this means there are infinite solutions

3 0
3 years ago
Trey bought 18 packs of cola. Each pack had 8 cans. He drank 7 of the cans. How many cans are left?
MariettaO [177]

Answer: 137 cans are left of cola.

Step-by-step explanation: First we want to find the total amount of cola Trey bought. Each pack contains 8 cans, so multiply 18 packs by 8 cans to find the total amount of cans he bought. 18 x 8 = 144 total cans of cola.

Since Trey drank 7 of the cans, simply subtract 7 from 144, 144 - 7 = 137 total cans of cola remaining.

5 0
3 years ago
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