A rectangle has a perimeter of 36 feet and a base of 14 feet. What is the height?

Mathematics

1 answer:

IrinaK [193]2 years ago

3 0

Answer:

The answer is 4.

Step-by-step explanation:

If this shape has a perimeter of 36, and the base has a length of 14, you subtract 36 - 28 because there are two sides that have a length of 14. You get 8 by subtracting 36 - 28, and divide the answer by 2.

You might be interested in

I'm thinking of a ten-digit integer whose digits are all distinct. It happens that the number formed by the first n of them is d

omeli [17]

The problem here takes a brilliant mind to answer this. This problem can easily be answered using programming because we can not then and there push all the possibilities using paper and pen.

The answer is <span>3816547290.
</span>
Trying all the possibilities starting form 1000000080 (we are sure that the last number should be 0). Then traversing that number until <span>9999999990. Each traverse, check the number if its divisible to n, so on and so forth.</span>

6 0

3 years ago

Mrrafil [7]

Let the length of the rectangle is x. units , accordingly :

2.(x+3) = x×3.

2x + 6 = 3x.

x = 6 units is the answer :)

8 0

3 years ago

Lapatulllka [165]

Could you show a picture so i could understand a little bit better?

6 0

3 years ago

Name four points in the figure

Kobotan [32]

-- ear lobe
-- knee
-- hip
-- elbow

7 0

4 years ago

Read 2 more answers

If the area of a baseball diamond (shape of a square) is 8100 ft squared, how would you find the distance from 1st base to 3rd b

Readme [11.4K]

Answer:

Exact distance = $90\sqrt{2}$ feet
Approximate distance = 127.2792 feet.

===========================================================

Explanation:

The area of the square is 8100 square feet, abbreviated ft^2.

Apply the square root to find the distance from any base to its adjacent counterpart (eg: from 1st to 2nd base). So we get sqrt(8100) = 90 ft as that side distance. Notice that 90*90 = 8100.

If you were to draw a line from 1st base to 3rd base, then you would split the square into two congruent right triangles. Each right triangle is isosceles (the two legs being 90 ft each).

Use the pythagorean theorem to find the hypotenuse.

$a^2 + b^2 = c^2\\\\c = \sqrt{a^2+b^2}\\\\c = \sqrt{90^2+90^2}\\\\c = \sqrt{2*90^2}\\\\c = \sqrt{2}*\sqrt{90^2}\\\\c = \sqrt{2}*90\\\\c = 90\sqrt{2} \ \text{ ... exact distance}\\\\c \approx 127.2792 \ \text{ ... approximate distance}\\\\$

The distance from 1st to 3rd base is roughly 127.2792 feet.

5 0

2 years ago