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Agata [3.3K]
3 years ago
9

A value increased by 5 then split the results three ways

Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

(x+5)/3

Step-by-step explanation:

Our value, x, is being increased by 5, so we just add 5. Then it is split 3 ways, so we just divide x+5 by 3 to get (x+5)/3

Hope this helps

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James has 16 balloons. 1/4 of his balloons are red. How many balloons does he have? 1/2 of his red balloons pop after ten minute
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Read 2 more answers
PLEASE FOR THE LORD JESUS PLEASE ANSWER ASAP!!!!!!!!!!!!!
ZanzabumX [31]

Answer:

Correct option: ninth one.

m∠CQD = 22°

m∠EQF = 33°

Step-by-step explanation:

as the segment BQG is a straight line, its angle is 180 degrees, so the sum of all those 5 angles is equal to 180 degrees. So, we have that:

m∠FQG + m∠EQF + m∠DQE + m∠CQD + m∠BQC = 180°

12 + 3x + 103 + 2x + 10 = 180

5x + 125 = 180

5x = 55

x = 11°

Then, we have that:

m∠CQD = 2x = 22°

m∠EQF = 3x = 33°

3 0
3 years ago
Find the following quotients, and write the quotient in standard form. (a)- x^2-9 ÷ x-3 (b)- x^3-27 ÷ x-3 (c) x^4- 81 ÷ x-3
IgorLugansk [536]

Answer:

(a) x+3

(b) x^2+3x+9

(c) (x+3)(x^2+9)

Step-by-step explanation:

We have given that

(a) \frac{x^2-9}{x-3}

From the algebraic identity we know that

a^2-b^2=(a+b)(a-b)

So \frac{x^2-9}{x-3}=\frac{(x+3)(x-3)}{x-3}=x+3

(b) \frac{x^3-27}{x-3}

We know the algebraic identity

a^3-b^3=(a-b)(a^2+ab+b^2)

So \frac{x^3-27}{x-3}=\frac{x^3-3^3}{x-3}=\frac{(x-3)(x^2+3x+9)}{x-3}=x^2+3x+9

(c) We have given \frac{x^4-81}{x-3}

We know the algebraic identity

a^2-b^2=(a+b)(a-b)

\frac{x^4-81}{x-3}=\frac{(x^2)^2-(3^2)^2}{x-3}=\frac{(x^2-9)(x^2+9)}{x-3}=\frac{(x+3)(x-3)(x^2+9)}{x-3}=(x+3)(x^2+9)

3 0
2 years ago
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