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Airida [17]
3 years ago
9

8m+3n-4m+7n help please

Mathematics
2 answers:
Lilit [14]3 years ago
7 0
8m+3n-4m+7n =\\
4m+10n
aliya0001 [1]3 years ago
4 0
8m +3n-4m +7n =
4m +10n
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Write the phrase as an algerbraic expression. 4 times the sum of a number and 20
Iteru [2.4K]
4 x (n + 20), pretty simple. :)
6 0
3 years ago
A tree casts a shadow 27 m long. At the same time, the shadow cast by a 66-cm tall statue is 56 cm long. Find the height of the
Nata [24]
\frac{height _{1} }{shadow_{1}} =  \frac{height _{2} }{shadow_{2}}

\frac{height _{1} }{27m} = \frac{66cm}{56cm}

\frac{height _{1} }{2700cm} = \frac{66cm}{56cm}

2700*66=56*h _{1}

178200=56h _{1}

3182.1cm=h _{1}

\frac{3182.1cm}{1000cm} = 3.2m

height:3.2m
6 0
3 years ago
Read 2 more answers
Help please! this is my third time posting this!! T.T
ArbitrLikvidat [17]

Answer:

see below

Step-by-step explanation:

24 - 3 x = -27

Subtract 24 from each side

24-24 - 3 x = -27-24

-3x =-51

Divide each side by -3

-3x/-3 = -51/-3

x = 17

Check

24 -3(17) = -27

24 -51 = -27

-27 = -27

8 0
3 years ago
Can someone show me hwo to do this so that i know how to do this please
spin [16.1K]

Answer:

y = -2x - 2

Step-by-step explanation:

3 0
1 year ago
Read 2 more answers
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
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