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3 years ago

What is domain and range in math

Mathematics

1 answer:

aksik [14]3 years ago

7 0

Answer:

range is the difference between big and small numbers

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The local movie theater reported loses of $175 each day for three days. What was the loss for the fourth day?

laila [671]

Answer: $700
explanation: they lost 175 EACH DAY
so 175 x 3 = 525
add another 175 for the fourth day
525 +175 = 700
They lost a total of $700 on the fourth day.

5 0

3 years ago

Question is worth 25 points what is 15 squared?

makkiz [27]

The answer is 225
15•15=225

7 0

4 years ago

Find the surface area for the given cylinder with the radius 6 and the height 24

Basile [38]

1130.97 is the surface area of the cylinder

6 0

3 years ago

Read 2 more answers

The sum of 5 consecutive integers is 120 what is the third number

Juliette [100K]

5 consecutive numbers that add up to 120 are:
22, 23, 24, 25, 26

As you can see the third term is 24.
The answer is 24

Hope it helps :)

4 0

3 years ago

Using the method of completing the square, put each circle into the form

tatiyna

Answer:

Standard form: $(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Center: $(\frac{1}{2}, 0)$

Radius: $r =\sqrt{15}$

Step-by-step explanation:

The equation of a circle in the standard form is

$(x-h)^{2} + (y-k)^{2} = r^{2}$

Where the point (h, k) is the center of the circle

To transform this equation $4x^{2} -4x + 4y^{2} - 59 = 0$ this equation in the standard form we use the method of square.

First, we group similar variables

$(4x^{2} -4x) + (4y^{2}) - 59 = 0$

Divide both sides of equality by 4

$(x^{2} -x) + (y^{2}) - 14.75 = 0$

Now we complete square for variable x.

Take the coefficient "b" that accompanies the variable x and divide by 2. Then, elevate the result to the square:

$b =-1\\\\\frac{b}{2}= \frac{-1}{2}= -\frac{1}{2}\\\\(\frac{b}{2})^2= (-\frac{1}{2})^2 = \frac{1}{4}$

Now add $(\frac{b}{2})^2$ on both sides of the equality

$(x^{2} -x +\frac{1}{4}) + (y^{2}) - 14.75 = (\frac{1}{4})$

Factor the expression and simplify the independent terms

$(x-\frac{1}{2})^2 + (y^{2}) = 15$

$(x-\frac{1}{2})^2 + (y-0)^2 = 15$

Then

$h =\frac{1}{2}\\\\k=0$

and the center is $(\frac{1}{2}, 0)$

radius $r =\sqrt{15}$

3 0

3 years ago