2/12 for the first one but I can't really figure out the second one
The answer i think is. If<span> the </span>length<span> of the </span>table<span> is </span>18 ft more than<span> the </span>width<span>, </span>x, which - 1447102. ... Thearea<span> of the </span>conference table<span> in </span>Mr<span>. </span>Nathan's office must<span> be </span>no more than 175 ft2<span> ... Therefore, the</span>interval<span> 0 < </span>x<span> ≤ 7 represents the possible widths</span>
Answer:
--- y intercept
Step-by-step explanation:
Given:
x = weeks; y = copies
The right parameters are:
After 1 week, 5840 copies were downloaded
After 5 weeks, 13090 copies were downloaded
So, the (x,y) forms are:
Next, we calculate the slope (m) using:
The equation is then calculated using:
To calculate the y intercept, substitute 0 for x
4x+2y<=16
3x+3y<=15
2x+y<=8
x+y<=5
3x+2y->maximize profit
X Y profit
1 4 11
2 3 12
3 2 13
4 0 12
3 1 11
3 2 13
2 3 12
1 4 11
0 5 10
Farmer need to make 3 Apple pies and 2 apple cobblers
Farmer will use 16 cups of apples and 15 cups of flour
profit of farmer will be $13
You haven't told me what the question is. But I put the mouse
to my forehead, closed my eyes, took a deep breath, and I could
see it shimmering in my mind's eye. It was quite fuzzy, but I think
the question is
"What score does Andrew need on the next test
in order to raise his average to 72% ?"
The whole experience drew an incredible amount of energy
out of me, and the mouse is a total wreck. So we'll just go ahead
and answer that one. I hope it's the correct question.
The average score on 4 tests is
(1/4) (the sum of all the scores) .
In order for Andrew to have a 72% average on 4 tests,
the sum of the 4 scores must be
(4) x (72%) = 288% .
Out of that total that he needs, he already has
(64% + 69% + 73%) = 206%
on the first three tests.
So in order to average 72% for all 4 tests,
he'll need to score
(288% - 206%) = 82%
on the fourth one.