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3 years ago

Find two conservative integers whose sum is 67

1 answer:

7 0

Answer:I got 33 and 34

Explanation:

Call your integers n and n+1 we get:

n+n+1= 67

rearrange:

2n = 66

n=66/2 = 33

The integers will be 33 and 34

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WILL MARK BRAINLIEST! PLEASE HELP! Write 206 in base 7

Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!$\*SuperscriptBox[\(Base$, $Power$]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0

2 years ago

Glenn, the owner of a hardware store, originally paid $54.60 for 15 tool sets. At his year-end clearance sale, he sold the last

Sonja [21]

The amount of money he lose on the last tool set is: $30.60.

<h3>Amount lose</h3>

Using this formula

Amount lose=Original amount paid -Selling price

Where:

Original amount paid=$54.60

Selling price=$24.00

Let plug in the formula

Amount lose=$54.60-$24.00

Amount lose=$30.60

Therefore the amount of money he lose on the last tool set is: $30.60.

Learn more about amount lose here:brainly.com/question/11872053

#SPJ1

3 0

2 years ago

Solve for x: geometry question plz help!!!

hoa [83]

Answer:

Step-by-step explanation:

But not too sure tho make sure of it

8 0

3 years ago

1. What is the constant of proportionality, k, of Kevin's wage? Greg's? Savannah's?

Gala2k [10]

Answer:

Part a) The constant of proportionality of Kevin's wage is $k=\$8.25\ per\ hour$

Part b) The constant of proportionality of Greg's wage is $k=\$9.00\ per\ hour$

Part c) The constant of proportionality of Savannah's wage is $k=\$9.50\ per\ hour$

Step-by-step explanation:

See the attached figure to better understand the problem

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $y/x=k$ or $y=kx$

To find out the constant of proportionality k , divide the variable y (total earned) by the variable x (number of hours)

Kevin's wage

Take any point from the table

I take the point (2,16.50)

$k=\frac{16.50}{2}=\$8.25\ per\ hour$

Greg's wage

Take any point from the table

I take the point (3,27.00)

$k=\frac{27.00}{3}=\$9.00\ per\ hour$

Savannah's wage

Take any point from the table

I take the point (2,19.00)

$k=\frac{19.00}{2}=\$9.50\ per\ hour$

3 0

3 years ago

Billy wants to find out which cafeteria food is the favorite in his school for students. He surveys 100 students. 29 students se

Pani-rosa [81]

9/25 it’s simplified

6 0

2 years ago

Read 2 more answers