Find K if x + 1 is a factor of P(x) = Kx^2-x+2
1 answer:
Answer:
Step-by-step explanation:
According to the Factor Theorem, a binomial (<em>x</em> - <em>a</em>) is a factor of a polynomial P(x) if and only if P(a) = 0.
We have the polynomial:
And we want to find the value of <em>K</em> such that (<em>x</em> + 1) is a factor.
We can rewrite our factor as (<em>x</em> - (-1)). Thus, <em>a</em> = -1.
Then in orer for (<em>x</em> + 1) to be a factor, P(-1) must equal 0. Hence:
Simplify:
Solve for <em>K. </em>Hence:
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Simple...
4.) -8-x=x-4x
So, what you want to do is isolate x.
Which means that you must move x to one side, and any other variables to the other side.
-8-x=x-4x
-8-x=-3x
-8-x=-3x
+x +x
-8=-2x
4=x
Thus, your answer.
To check your work...plug in x.
-8-x=x-4x
-8-4=4-4(4)
-12=4-(16)
-12=-12
Thus, you know your answer is correct.
4.) -8-x=x-4x
So, what you want to do is isolate x.
Which means that you must move x to one side, and any other variables to the other side.
-8-x=x-4x
-8-x=-3x
-8-x=-3x
+x +x
-8=-2x
4=x
Thus, your answer.
To check your work...plug in x.
-8-x=x-4x
-8-4=4-4(4)
-12=4-(16)
-12=-12
Thus, you know your answer is correct.