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2 years ago

6

The elgebaric expression for 5y to the product of a and b.

1 answer:

LenKa [72]2 years ago

4 0

Answer:

$5y^a^*^b$

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For function of g,g(0)=1 and g(1)=5 assuming g is a linear function what is g(3)<br>

lawyer [7]

Answer:

$g(3) = 13$

Step-by-step explanation:

Given

$g(0) = 1$

$g(1) = 5$

Required

Find g(3)

Since g(x) is a linear function, then:

$g(x) = mx + c$

For: $g(0) = 1$

$g(x) = mx + c$

$g(0) = m*0 + c$

$1 = 0 + c$

$1 = c$

$c = 1$

For: $g(1) = 5$

$g(x) = mx + c$

$g(1) = m * 1 + c$

$5 = m * 1 + c$

$5 = m + c$

Substitute $c = 1$

$5 = m + 1$

$m = 5 - 1$

$m =4$

So, the function is:

$g(x) = mx + c$

$g(x) = 4x + 1$

Calculate g(3)

$g(3) = 4*3 + 1$

$g(3) = 12 + 1$

$g(3) = 13$

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