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Natalija [7]
2 years ago
9

Help:

D0" id="TexFormula1" title="1.\ &x^4-61x^2+900=0 \\ 2. \ & x^4-25x^2+144=0" alt="1.\ &x^4-61x^2+900=0 \\ 2. \ & x^4-25x^2+144=0" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
yawa3891 [41]2 years ago
7 0

\bf{1) \  x^4-61x^2+900=0 }

Applying the factorization method, for example:

      \bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}

               \bf{\\ &=(x+6)(x-6)(x+5)(x-5);    }

              \bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5  }

\bf{2) \  x^4-25x^2+144=0  }

Applying the factorization method:

          \bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }

             \bf{ =(x-4)(x+4)(x-3)(x+3); }

            \bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3  }

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Answer:

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C. Miguel is inconsistent with the time set for training compared to that of Adam.

Step-by-step explanation:

The spread of a data shows the range of the data.

Using the range to determine the spread of the given data:

A. The range of the two persons can be determined by:

          Range = highest value - lowest value

So that:

Adam's range = 106 - 91

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Comparing the range of the two, Miguel has the greatest spread.

B. Considering the middle 50% of the training time;

Adam - 103 105 104 106 100

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Adam's 50% range = 106 - 100

                               = 6

Miguel's 50% range = 105 - 86

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Considering the middle 50% of the training time, the person with the least spread is Adam.

C. The answers to parts 2(a) and 2(b) shows that; there is a wide variation (much inconsistency) in the time that Miguel spend during training, but a minimum variation in the time spent by Adam during training.

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3 years ago
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dybincka [34]

Answer:

38°

Step-by-step explanation:

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