All categories

2 years ago

F(x)=2x+3 and g(x)=4x-2. Find f(x) x g(x). Find f(x) - g(x).

Mathematics

1 answer:

const2013 [10]2 years ago

3 0

Answer:

f(x) * g(x) is 8x^2 + 8x -6

f(x) - g(x) is -2x + 5

Step-by-step explanation:

When finding the answer, we can notice they already give the values for the needed answers.

The first one requires f(x) and g(x). At the beginning of the question it shows that f(x) is equal to 2x+3. Meaning we can plug in 2x+3 for f(x).

The same goes for g(x). At the begginning of the question, it shows that g(x) is equal to 4x-2. Meaning we can plug in 4x-2 for g(x).

f(x) * g(x)

(2x+3) * (4x-2)

To find the answer, we need to distibute the 2x+3 into 4x-2.

To distribute, we do :

2x * (4x-2) + 3 * (4x-2)

First we distribute the 2x

2x * 4x = 8x^2 and 2x * -2 = -4x

8x^2 - 4x

Next we distibute the 3

3 * 4x = 12x and 3 * -2 = -6

12x - 6

Now we can combine them by adding like terms to get the asnwer:

8x^2 = 8x^2

-4x + 12x = 8x

-6 = -6

The first answer is 8x^2 + 8x -6

Second question:

Since we already know the values for f(x) and g(x), all we have to do is plug in the values.

(2x+3) - (4x-2)

This time, since we are subtracting, all we have to do is subtract like terms.

2x - 4x = -2x

3 - (-2) = 5

The second answer is -2x + 5

You might be interested in

True false test consists of 10 questions how many ways can a student mark one answer to each answer

ololo11 [35]

2^10 = 1024 possible ways to answer the test

8 0

3 years ago

A computer program contains one error. In order to find the error, we split the program into 6 blocks and test two of them, sele

Aleksandr-060686 [28]

There are $\dbinom62$ ways of selecting two of the six blocks at random. The probability that one of them contains an error is

$\dfrac{\dbinom11\dbinom51}{\dbinom62}=\dfrac5{15}=\dfrac13$

So $X$ has probability mass function

$f_X(x)=\begin{cases}\dfrac13&\text{for }x=1\\\\\dfrac23&\text{for }x=0\end{cases}$

These are the only two cases since there is only one error known to exist in the code; any two blocks of code chosen at random must either contain the error or not.

The expected value of finding an error is then

$\displaystyle\sum_{x=0}^1xf_X(x)=0\times\dfrac23+1\times\dfrac13=\dfrac13$

7 0

3 years ago

In a school there are 1000 boys and 800 girls. Calculate the percentage of boys and girls

Arisa [49]

Answer:

55.55%= boys & 44.44% = girl

Step-by-step explanation:

1000/(1000+800)=1000/1800=.5555 or 55.55% are boys

800/(1000+800)=800/1800=.4444 or 44.44% are girls.

Therefore, 55,55% are boys and 44.44% are girls.

8 0

3 years ago

Amelia wants to paint three walls in her family room. Two walls are 26 feet long by 9 feet wide. The other wall is 18 feet long

sattari [20]

Given:
Wall 1 & 2 : 26 ft by 9 ft
Wall 3 : 18 ft by 9 ft

Area 1 : 26 ft x 9 ft = 234 ft²
Area 2 : 26 ft x 9 ft = 234 ft²
Area 3 : 18 ft x 9 ft = 162 ft²

Total Area : 234 ft² + 234 ft² + 162 ft² = 630 ft²

1 Gallon = 250 ft²

630 ft² ÷ 250 ft² per gallon = 2.52 gallons

6 0

3 years ago

What is the conditional probability that exactly four heads appear when a fair coin is flipped five times

cestrela7 [59]

Answer:

5/32

Step-by-step explanation:

If a coin if flipped five times with four heads, then it has exactly one tail. The number of way to arrange four heads and one tail are as follows:

T H H H H

H T H H H

H H T H H

H H H T H

H H H H T

Essentially, there are five way because there are five "positions" where the tail could be.

Then, you need to find the total amount of possibilities for flipping a coin five times. Every time you flip it, there are two possibilities- heads and tails. Therefore, for five flips, the total amount of possibilities is

2x2x2x2x2 = 32

You know that

probability= # of desired outcome

----------------------------------

# of total outcomes

So the probablity is 5/32.

8 0

3 years ago