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2 years ago

Whats the area of this shape?

Mathematics

1 answer:

vodomira [7]2 years ago

8 0

The area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.

<h3>What is the area of the kite figure?</h3>

The area of the kite figure is half of the product of its diagonals. Area of kite figure can be find out using the following formula.

$A=\dfrac{pq}{2}$

Here, p and q are the diagonals of the kite.

The length of the first diagonal of the kite figure is,

p=6+15

p=21 cm

The length of the second diagonal of the kite figure is,

q=8+8

q=16 cm

Thus, the area of kite figure is:

$A=\dfrac{21\times16}{2}\\A=\dfrac{21\times16}{2}\\A=168\rm\; cm^2$

Thus, the area of the shape shown in the image which is in the shape of kite figure is 168 squared centimeters.

Learn more about the area of kite here;

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Samir is an expert marksman. When he takes aim at a particular target on the shooting range, there is a 0.950.950, point, 95 pro

Vinvika [58]

Answer:

40.1% probability that he will miss at least one of them

Step-by-step explanation:

For each target, there are only two possible outcomes. Either he hits it, or he does not. The probability of hitting a target is independent of other targets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

0.95 probaiblity of hitting a target

This means that $p = 0.95$

10 targets

This means that $n = 10$

What is the probability that he will miss at least one of them?

Either he hits all the targets, or he misses at least one of them. The sum of the probabilities of these events is decimal 1. So

$P(X = 10) + P(X < 10) = 1$

We want P(X < 10). So

$P(X < 10) = 1 - P(X = 10)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{10,10}.(0.95)^{10}.(0.05)^{0} = 0.5987$

$P(X < 10) = 1 - P(X = 10) = 1 - 0.5987 = 0.401$

40.1% probability that he will miss at least one of them

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3 years ago

What are the Rates of Change and the initial values to these? If you don't have the answer I'll take an explanation on how to do

gogolik [260]

Step-by-step explanation:

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y(#2) - y(#1)

------------------ = Divided by

x(#2) - y(#1)

This formula will calculate the rate of change. I will do the first one for you as follows.

The first point I would find would be (1,3). 1 space on the X-axis, 3 on the Y-axis.

To write a ordered pair to represent the point on the plane, use the (X,Y).

Then, I'd find the second point.

Following the second point, I would do the equation like so.

y(2) - 3

-----------------

x(2) - 1

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3 years ago

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