Exponential model is y=Ae^(kt)
Assume initial start is 2005, time = 0, so y = 18000e^(kt)
45000 = 18000*e^(k5)
solve for k, approx 0.1832
y = 18000*e^(1.832) = 112,435, approximately
Answer:
1/5
Step-by-step explanation:
Use Pythagoras theorem
We can set up this equation using this formula:
a = p(1 + r/n)^nt
p = starting amount.
r = interest.
n = number of times it's compounded in a year
t = years
We'd set it up like this:
a = 50(1 + ?/1)^1(12)
Because we're missing the amount of interest, it would be impossible to tell what the amount would be after 12 years.
<h2>
Answer:
<u><em>
</em></u></h2>
Step-by-step explanation:
Step 1: Multiply the whole number part (1) by the denominator (8).
1 × 8 = 8
Step 2: Add the product from Step 1 (8) to the numerator (4).
8 + 4 = 12
Step 3: Write that result (12) above the denominator. So,
Step 4: The fraction 
Can be reduced by dividing both numerator and denominator by the GCD(12,8) = 4. Thus,
17.05 I think..
this could be it idrk what it is
