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Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.
<h3 /><h3>What is the frequency distribution about?</h3>Temperature (°F) Frequency
40-44 1
45-49 3
50-54 5
55-59 11
60-64 7
65-69 7
70-74 1
A. Viewing at the frequency table, we find that the lower class limits of two consecutive classes are 40 and 44, respectively. Thus the class width is:
Class width = 44 − 40= 4
B: One can find the class midpoints by putting the average of the lower and upper class limits. So the midpoint of the first class is seen below:
= 40 - 44 = = 42. In a similar way, we find the rest.
C. The Class boundaries is known to be that which separate the classes removing the class limits. The class boundaries are as follows:
43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5
Therefore, Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.
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Pemdas
parenthases (none)
exponents
multiplication so
exponents
c^0.5
so 0.5=1/2 and if you have
x^(z/t)=![\sqrt[t]{x^z}](https://tex.z-dn.net/?f=%20%5Csqrt%5Bt%5D%7Bx%5Ez%7D%20)
so
c^1/2=![\sqrt[2]{c^1} or \sqrt{c}](https://tex.z-dn.net/?f=%20%5Csqrt%5B2%5D%7Bc%5E1%7D%20or%20%20%5Csqrt%7Bc%7D%20%20)
so
multiplication
-9 times √c is the answer or more commonly written as
-9√c
parenthases (none)
exponents
multiplication so
exponents
c^0.5
so 0.5=1/2 and if you have
x^(z/t)=
c^1/2=
multiplication
-9 times √c is the answer or more commonly written as
-9√c
Answer:
The answer is B 10 L
Step-by-step explanation:
let milk and water in the mixture be 7x and 4x equal 55L
let x Liters of water he added so that the ratio is 7:6
cross multiply