Answer:
The area of the figure is;
A = 2,112 in²
Step-by-step explanation:
The given figure is a composite figure consisting of a rectangle AINE and a triangle AIL
The dimensions of the rectangle AINE are;
Length, L = 48 in.
Height, h = 32 in.
The area of the rectangle AINE, A₁ = Length, L × Height, h
∴ A = L × h = 48 in. × 32 in. = 1,536 in.²
The area of the triangle AIL, A₂ = 1/2 × Base × Height of the triangle
The base length of the triangle, L = IA = 48 in.
The height of the triangle, ht = 12 in.
∴ A₂ = L × ht
A₂ = 48 in. × 12 in. = 576 in.²
The area of the triangle AIL, A₂ = 576 in.²
The area of the figure, A = The area of the rectangle, A₁ + The area of the triangle, A₂
A = A₁ + A₂
∴ A = 1,536 in.² + 576 in.² = 2,112 in.²
The area of the figure, A = 2,112 in².
