Answer:
<u>Solution</u><u> </u><u>given</u><u>:</u>
<u>one</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u> </u><u>must</u><u> </u><u>be</u><u> </u><u>less</u><u> </u><u>than</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>of</u><u> </u><u>two</u><u> </u><u>other</u><u> </u><u>side</u><u> </u><u>.</u>
<u>by</u><u> </u><u>making</u><u> </u><u>these</u><u> </u><u>sense</u><u>:</u>
3<10+20
10<20+3
20<10+3not true
these three side are not possible.
again
10<20+25
20<25+10
25<20+10
these three side are true so
required side are:
Side 1:10
Side 2:25
Side 3:20
The answer to that would be D!
<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3
Answer:
It is in standard form!!!
:)
<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3<3
Answer: 0.0546875
Step-by-step explanation:
The number of times the coin landing head 8 out of 10 is simply:
C(10, 8)/2^10. At least 8 means, 8 or more. Since the events here are dependent on themselves the answer would be:
[ C(10, 8) + C(10, 9) + C(10, 10) ] / 2^10 = 56/1024 = 0.0546875