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lutik1710 [3]
3 years ago
6

Please help ! no links please

Mathematics
1 answer:
vodka [1.7K]3 years ago
5 0
All triangles must have angles that add up to the same amount of degrees, so if the two triangles share one exact point, it is assumed that those angles would be the same. Basically just use the fact that the sides are the same and marked by dashes, and the missing line can be proven with the use of the angles that are in between the point that both share.
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Leon drew 2 fraction cards that were between 1/6 and 1/2. The sum of the 2 cards are between?
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fndadhfuhadifhaStep-by-step explanation:

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Each saddle has exactly two saddle bags on it
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76 19 in ratio simplest form
Nata [24]
Putting the two numbers together in fraction form of a ratio, we have 76/19. We know that something multiplied by 19 will equal to 76.

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8 0
3 years ago
CAN SOMEONE PLEASE HELP ME ASAP PLEASEEEE!!!​
Rom4ik [11]

Answer:

11.4

Step-by-step explanation:

So we know that Triangle ACB is similar to Triangle EFD.

This means that their sides are proportional to each other.

We want to find x or side AB. To do so, we can set up a proportion.

The proportional side to AB is ED. Let's also use BC since we know its value. The proportional side to BC is DF. Thus:

\frac{AB}{ED}=\frac{BC}{DF}

Substitute x for AB, 3.8 for Ed, 15 for BC, and 5 for DF. Thus:

\frac{x}{3.8}=\frac{15}{5}

Reduce the right:

\frac{x}{3.8}=\frac{3}{1}

Cross multiply:

x=11.4

So, the value of x is 11.4

And we're done!

7 0
3 years ago
For a binomial distribution with p = 0.20 and n = 100, what is the probability of obtaining a score less than or equal to x = 12
notsponge [240]
The binomial distribution is given by, 
P(X=x) =  (^{n}C_{x})p^{x} q^{n-x}
q = probability of failure = 1-0.2 = 0.8
n = 100
They have asked to find the probability <span>of obtaining a score less than or equal to 12.
</span>∴ P(X≤12) = (^{100}C_{x})(0.2)^{x} (0.8)^{100-x}
                    where, x = 0,1,2,3,4,5,6,7,8,9,10,11,12                  
∴ P(X≤12) = (^{100}C_{0})(0.2)^{0} (0.8)^{100-0} + (^{100}C_{1})(0.2)^{1} (0.8)^{100-1} + (^{100}C_{2})(0.2)^{2} (0.8)^{100-2} + (^{100}C_{3})(0.2)^{3} (0.8)^{100-3} + (^{100}C_{4})(0.2)^{4} (0.8)^{100-4} + (^{100}C_{5})(0.2)^{5} (0.8)^{100-5} + (^{100}C_{6})(0.2)^{6} (0.8)^{100-6} + (^{100}C_{7})(0.2)^{7} (0.8)^{100-7} + (^{100}C_{8})(0.2)^{8} (0.8)^{100-8} + (^{100}C_{9})(0.2)^{9} (0.8)^{100-9} + (^{100}C_{10})(0.2)^{10} (0.8)^{100-10} + (^{100}C_{11})(0.2)^{11} (0.8)^{100-11} + (^{100}C_{12})(0.2)^{12} (0.8)^{100-12}


Evaluating each term and adding them you will get,
P(X≤12) = 0.02532833572
This is the required probability. 
7 0
4 years ago
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