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Colt1911 [192]
3 years ago
13

A box of chocolates contains milk chocolates and dark chocolates in the ratio 4:3

Mathematics
2 answers:
Sergeeva-Olga [200]3 years ago
7 0

Answer:

20 milk chocolates

Step-by-step explanation:

The first step is adding together 4 + 3. You will get 7. This is the total number of units in the box.

Then, divide 35 by 7. You will get 5 as the answer.

To find the number of milk chocolates, multiply 5 and 4. You will get 20 as the answer.

WINSTONCH [101]3 years ago
6 0
4x+3x=35
7x=35
x=5

milk chocolate 4(5) = 20
dark chocolate 3(5) = 15
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Write a formula for function f in terms of function g.
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\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}


so hmm if you notice, your f(x) there, looks just like g(x), but is "shifted horizontally" by about 9 units to the right

that simply means, based on that template above, that C/B = -9, and we can simply make B = 1  and C = -9, and we get C/B = -9/1 which is -9

thus   \bf \begin{array}{llcll}
f(x)=g(&1x&-9)\\
&\uparrow &\uparrow \\
&B&C
\end{array}\iff f(x)=g(x-9)
7 0
3 years ago
Joe the trainer has two solo workout plans that he offers his clients: Plan A and Plan
sasho [114]
Let workout Plan A last a hours, and Plan B last b hours.

we are assuming personal training for each client.

i)
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the total time spent is : 2*a + 3*b =2a+3b

ii)
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the total time spent was 4*a+8*b=4a+8b

iii) "Joe trained his Monday clients for a total of 7 hours"

so 2a+3b = 7

iv)

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so 4a+8b=17

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4a+8b=17

multiply the first equation by -2, and then add both equations, to eliminate a:

-4a-6b=-14
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-------------------
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multiply by 2:
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a=5/4

Answer :

Plan A lasts 5/4=1.25 h
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Step-by-step explanation:

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