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Elza [17]
2 years ago
7

Pls help me do today

Mathematics
1 answer:
Irina-Kira [14]2 years ago
8 0

Answer:

\overline{OT}=\textsf{line segment OT}

Step-by-step explanation:

\overline{OT}=\textsf{line segment OT}

\angle OT=\textsf{angle OT}

\longleftrightarrow\\OT=\textsf{line OT}

\overrightarrow{OT}=\textsf{ray OT}

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Tomtit [17]
It is the first choice. 3 times 5/2 is 15/2 which equals 7.5 and 12 times 5/2 is 60/2 which equals 30. 7.5 times 30.
3 0
4 years ago
Read 2 more answers
. A firm produces a commodity and receives $100 for each unit sold. The cost of producing and selling x units is 20x + 0.25x 2 d
kirza4 [7]
So for each unit they get $100, so if they sell "x" units, they intake 100x, that's just the gross income, and therefore the Revenue.

Now, they have a cost of 20x + 0.25x² if they "x" units, now, bearing in mind that if you pluck out the costs out of the incoming revenue, what's leftover, is a surplus amount, namely the Profit.  Therefore, profit p(x) = revenue - costs, or  100x - (20x + 0.25x²), which is p(x) = -0.25x² +80x.

a)
now, what's the highest profit they can make?  check the picture below.

\bf p(x)=-0.25x^2+80x\\\\
-------------------------------\\\\
\textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lcclll}
p(x) = &{{ -0.25}}x^2&{{ +80}}x&{{ +0}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{80}{-0.50}~,~0-\cfrac{80^2}{-1} \right)\implies \left( \stackrel{\textit{quantity}}{160}~,~\stackrel{\textit{profit value}}{6400}  \right)

b)

well, if a tax is imposed on them, and say, they take it out of the revenue, then their new revenue is not 100x, is 90x, thus   \bf p(x)=-0.25x^2+70x

and you can use the same formula as above to get the x-coordinate for that vertex.

\bf p(x)=-0.25x^2+70x\\\\
-------------------------------\\\\
\textit{ vertex of a vertical parabola, using coefficients}\\\\
\begin{array}{lcclll}
p(x) = &{{ -0.25}}x^2&{{ +70}}x&{{ +0}}\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)
\\\\\\
\left( -\cfrac{70}{-0.50}~,~0-\cfrac{70^2}{-1} \right)

7 0
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Answer:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

8 0
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