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user100 [1]
2 years ago
6

Two different shaped containers have the same pressure, temperature and volume. What else must be true?

Chemistry
1 answer:
anyanavicka [17]2 years ago
3 0

Answer:

n, the number of moles of gas is the same

Explanation:

PV = n RT     if    P  and V and T  and R are the same , the n must be the same

n = numer of moles

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An unknown compound contains only carbon, hydrogen, and oxygen (CxHyOz). Combustion of 6.00 g of this compound produced 8.80 g o
cricket20 [7]

Answer:

There were 0.20 moles Carbon in the original sample

There were 0.40 moles hydrogen in the original sample

Explanation:

Step 1:  The balanced equation

CxHyOz + O2 → CO2 + H2O

Step 2: Data given

mass of the unknown compound = 6.00 g

mass of carbon dioxide produced = 8.80 g

mass of water produced = 3.60 g

Molar mass of Carbon = 12.01 g/mole

Molar mass of Hydrygen = 1.01 g/mole  ; 2.02 for H2

Molar mass of Oxygen = 16 g/mole

Molar mass of CO2 = 44.01 g/mole

Molar mass of H2O = 18.02 g/mole

Step 3: Calculate mass

8.80 g CO2 * 12.01 g/mole / 44.01 g/mole = 2.40 g carbon

3.60 g H2O * 2.02 g/mole / 18.02 g/mole = 0.404 g hydrogen

6.00 g total - 2.40 g carbon - 0.404 g hydrogen = 3.196 g oxygen

Step 4: Calculate number of moles

moles = mass / Molar mass

Mass of  Carbon = 2.40g / 12.01 g/mole = 0.20 mole Carbon

Mass of hydrogen = 0.40 g / 1.01 g/mole = 0.40 mole Hydrogen

4 0
3 years ago
How many grams are in 0.220 mol of Ne?
kumpel [21]

Answer:

4.44 g Ne

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

0.220 mol Ne

<u>Step 2: Identify Conversions</u>

Molar Mass of Ne - 20.18 g/mol

<u>Step 3: Convert</u>

<u />0.220 \ mol \ Ne(\frac{20.18 \ g \ Ne}{1 \ mol \ Ne} ) = 4.4396 g Ne

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

4.4396 g Ne ≈ 4.44 g Ne

3 0
3 years ago
Read 2 more answers
This scientist led a series of experiments that used high speed lightweight atoms called alpha particles to bombard very thin pi
ss7ja [257]

Answer:

B. Ernest Rutherford

Explanation:

Ernest Rutherford was a renown Physicist and a Physics Nobel price winner. In 1911 he proposed the planetary model of atom. When the experiment were conducted he proposed that the atom had a charged nucleus and are surrounded by electrons. This finding was the basis for subsequent studies on radioactivity.

3 0
3 years ago
A 15.0 L tank of gas is contained at a high pressure of
Inessa05 [86]

Answer:

20.5 torr

Explanation:

Given parameters:

Volume of tank  = 15L

Pressure of tank  = 8.2 x 10⁴torr

Volume of empty chamber = 6.0 x 10⁴L

Unknown:

New pressure of the gas in this chamber = ?

Solution:

To solve this problem, a good knowledge of the gas law will suffice here. Since pressure and volume relationships are under consideration, the Boyle's law is the proper gas law to apply.

 Boyle's law states that "at constant temperature, the volume of fixed mass of gas is inversely proportional to the pressure of the gas".

Mathematically;

    (Pressure x volume) of tank  = (Pressure x volume ) of empty chamber

      15 x 8.2 x 10⁴   = Pressure of empty chamber x 6 x 10⁴

 Pressure of empty chamber = 20.5 torr

7 0
3 years ago
Which of the following is not a conjugate acid-base pair? A) NH4+/NH3 B) H30-OH OC) H2SO3/HSO3 D) C2H302-/HC2H302
raketka [301]

Answer : The option (d) is not a conjugate acid-base pair.

Explanation :

According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.

Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.

(a) The equilibrium reaction will be,

NH_4^++OH^-\rightleftharpoons NH_3+H_2O

In this reaction, NH_4^+/NH_3 are act as a conjugate acid-base.

(b) The equilibrium reaction will be,

H_3O^++OH^-\rightleftharpoons H_2O+H_2O

In this reaction, H_3O^+/OH^- are act as a conjugate acid-base.

(c) The equilibrium reaction will be,

H_2SO_3+OH^-\rightleftharpoons HSO_3^-+H_2O

In this reaction, H_2SO_3/HSO_3^- are act as a conjugate acid-base.

(d) The equilibrium reaction will be,

C_2H_3O_2^-+H_2O\rightleftharpoons HC_2H_3O_2+OH^-

In this reaction, C_2H_3O_2^-/HC_2H_3O_2 are act as a conjugate base-acid.

Hence, from this we conclude that, the option (d) is not a conjugate acid-base pair but it is a act as conjugate base-acid.

6 0
3 years ago
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