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kobusy [5.1K]
3 years ago
6

You make a solution by putting 45.6g of iron lll carbonate into 167ml of water. What is it's molarity?

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
4 0
1. The molar mass of Fe2(CO3)3 is 291.72 g/mol. This means that 45.6 g is equivalent to 0.156 mol. Dividing by the 0.167 L of water gives a solution of 0.936 M.
2. Multiplying (0.672 M)(0.025 L) = 0.0168 mol. The molar mass of Ni(OH)2 is 92.71 g/mol, so multiplying by 0.0168 mol = 1.56 grams. Therefore you would need to dissolved 1.56 g of Ni(OH)2 into 25 mL of water.
3. Fe2(CO3)3 + Ni(OH)2 --> Fe(OH)3 + NiCO3Balancing: Fe2(CO3)3 + 3Ni(OH)2 --> 2Fe(OH)3 + 3NiCO3The reaction quotient is:[Fe(OH)3]^2 * [NiCO3]^3 / [Fe2(CO3)3][Ni(OH)2]^3= (0.05)^2 * (1.45)^3 / (0.936)(0.672)^3= 0.0268Since this is < 1, it implies that the reactants are favored at equilibrium.
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Use the question marck Moles of CO2
The the giving = 0.624 mol O2
Find the CF faction = 1 mole=  32.00 of O2

O= 2x16.00= 32.00amu ( writte this in the cf fraction)
SET UP THE CHART
Always start with the giving

0.624 mol O2    /  1mol of CO2
___________  / _____________ = Cancel the queal ( O2)
                       / 32.00c O2
                      /
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Multiply the top and divide by the bottom 
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You should look at the giving number ( how many num u gor ever there) 
Ur answer should have the same # as ur givin so 
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<em>Check the image below:</em>

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