Answer:
Five molecules of oxygen.
Explanation:
Hello,
In this case, considering the given chemical reaction, we must write a five before the oxygen in order to equal the number of oxygen atoms at both the right and left side (ten) so phosphorous remain the same (4):
![P_4(s) + 5 O_2(g)\rightarrow P_4O_{10}(s)](https://tex.z-dn.net/?f=P_4%28s%29%20%2B%205%20O_2%28g%29%5Crightarrow%20%20P_4O_%7B10%7D%28s%29)
It means that five molecules of oxygen (O₂) are needed to form one molecule of tetraphosphorous decaoxide (P₄O₁₀).
Best regards.
Answer: ![Rate=k[A][B]](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5BB%5D)
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
Order of the reaction is defined as the sum of the concentration of terms on which the rate of the reaction actually depends. It is the sum of the exponents of the molar concentration in the rate law expression.
For reactions which takes place in multiple steps are complex reactions and the order is given by the slowest step which is the rate limiting step.
For the given reaction, the rate limiting step is
![A+B\rightarrow D](https://tex.z-dn.net/?f=A%2BB%5Crightarrow%20D)
Rate law will be , ![Rate=k[A][B]](https://tex.z-dn.net/?f=Rate%3Dk%5BA%5D%5BB%5D)
<span>it says that all particles of matter are in constant motion </span>
Answer:
Equation 2, because Fe is being more reactive, replaces Cu from CuSO₄.
Explanation:
- Equation 1 is: <em>CuSO₄ + 2NaOH → Na₂SO₄ + Cu(OH)₂.</em>
The reaction between CuSO₄ and NaOH will give Na₂SO₄ and Cu(OH)₂ which is a precipitate "replacement reaction".
- While, equation 2 is: <em>CuSO₄ + Fe → Cu + FeSO₄.</em>
The reaction between CuSO₄ and Fe will produce Cu and FeSO₄.
Thus, it is used to extract Cu because Fe is more reactive than Cu, so it can replace it in its salts and Cu can be extracted.
- <em>So, the right choice is: Equation 2, because Fe is being more reactive, replaces Cu from CuSO₄.</em>
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Answer:
Raw natural gas is commonly collected from a group of adjacent wells and is first processed at that collection point for removal of free liquid water and natural gas condensate. The condensate is usually then transported to an oil refinery and the water is disposed of as wastewater.
Explanation: