Dividing 4x by 4 isolates x on one side of the equation
Answer:
The answer to this equation would be -19
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The answer is square root of 6.909877
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Answer:
y = 3/4x - 9/8
Then read explanation and see here with 2 coordinates would make
if 3/4 = -6 then 1 = -8
y = -6x + c
-6 / 3/4 + 9/8 / - 0.5 = -2.25
therefore c = -2.25
y = -6x - 2.25
y = -6x - 9/4 and again 9/4 can be found easily if round up fraction decimal to 225/100 and divide by 4
Step-by-step explanation:
C1) (0.5 , -0.75)
C2) ( 1. -3.75)
y = mx + c
-3.75 - - 0.75 / 1 - 0.5 = -3.75 + 0.75 / 0.5
= -3 / 0.5 = m
m = -6
y = -6x + c
then this works given just one coordinate to solve for 1 or 2 sets given points
y - y1 = mx+c
y - - 0.75 = 0.75 (x - x1)
y + 0.75 = 0.75 (x - 0.5)
y + 0.75 = 0.75x - 0.375
y = 0.75 - 0.75 = 0.75x( - 0.375 - 0.75)
y = 0.75x -1.125
y = 3/4x - 9/8 as common denominators of 1125/1000 is 9/8 as we divide by 125 into the fraction as we start at 250 and check its half just like when finding common denominators we 1/4 the lower number and see if we can find its half or its double etc with the other num er as first step for 3sf numbers.
Answer:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
Step-by-step explanation:
The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.
The first quartile(Q1) separates the lower 25% from the upper 75% of a set. So 25% of the values in a data set lie at or below the first quartile, and 75% of the values in a data set lie at or above the first quartile.
The third quartile(Q3) separates the lower 75% from the upper 25% of a set. So 75% of the values in a data set lie at or below the third quartile, and 25% of the values in a data set lie at or the third quartile.
The answer is:
Complete the following statements. In general, 50% of the values in a data set lie at or below the median. 75% of the values in a data set lie at or below the third quartile (Q3). If a sample consists of 500 test scores, of them 0.5*500 = 250 would be at or below the median. If a sample consists of 500 test scores, of them 0.75*500 = 375 would be at or above the first quartile (Q1).
